How to modify command line arguments inside bash script using set

Question

I'm executing a shell script and passing few command line arguments to it.

I want to modify the arguments inside the script using set. Not all at once depending upon some conditions.

How can I do that?

./check_test_results.sh $publish_pcom_test $publish_svs_test This is how I'm executing the script. The two arguments are having some default values(True/False). I want to do some operations and want to decide whether I have to modify these argument values or not. If I have to update these values then how can I do that? — BMD
– BMD, Commented Apr 8, 2020 at 8:47
You can access parameter using $1 and $2 Check this thread --> stackoverflow.com/questions/192249/… — Digvijay S
– Digvijay S, Commented Apr 8, 2020 at 9:05
@DigvijayS it's not about accessing it, I want to update $1 $2 with some new values using set — BMD
– BMD, Commented Apr 8, 2020 at 9:08
You want to update value of $publish_pcom_test $publish_svs_test right ? try export $publish_pcom_test="Blah blah " — Digvijay S
– Digvijay S, Commented Apr 8, 2020 at 9:11

Léa Gris · Accepted Answer · 2020-04-08 10:36:09Z

2

Copy unmodified arguments at their respective location within set --

Say you want to modify value of argument 2:

set -- "${@::2}" 'new arg2 value' "${@:3}"

Explanation:

"${@::2}": Expands 2 arguments from index 0 (arguments 0 and 1)
new arg2 value: Becomes the value for argument 2.
"${@:3}": Expands all argument values starting at index 3.

Opinion:

Anyway, having mutable arguments is considered code-smell in modern programming. So I'd recommend you reconsider your approach to the problem you are trying to solve.

edited Apr 8, 2020 at 10:36

answered Apr 8, 2020 at 10:29

Léa Gris

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