Extract a string in linux shell script

Question

Guys i have a string like this:

variable='<partyRoleId>12345</partyRoleId>'

what i want is to extract the value so the output is 12345.

Note the tag can be in any form: <partyRoleId> or <ns1:partyRoleId>

any idea how to get the tag value using grep or sed only?

Don't Parse XML/HTML With Regex. I suggest to use an XML/HTML parser (xmlstarlet, xmllint ...). — Cyrus
– Cyrus, Commented Apr 4, 2020 at 20:32

choroba · Accepted Answer · 2020-04-04 20:12:26Z

2

Use an XML parser to extract the value:

echo "$variable" | xmllint -xpath '*/text()' -

You probably should use it for the whole XML document instead of extracting a single line from it into a variable, anyway.

answered Apr 4, 2020 at 20:12

choroba

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2 Comments

yarab yarab Over a year ago

i wqnt to used grep or sed only

choroba Over a year ago

@yarabyarab: These tools are not good for parsing XML. Do you know that the element can also be equivalently written as <partyRoleId><![CDATA[12345]]></partyRoleId>?

Saboteur · Accepted Answer · 2020-04-04 23:44:41Z

0

to use only grep, you need regexp to find first closing brackets and cut all digits:

echo '<partyRoleId>12345</partyRoleId>'|grep -Po ">\K\d*"

-P means PCRE -o tells to grep to show only matched pattern and special \K tells to grep cut off everything before this.

answered Apr 4, 2020 at 23:44

Saboteur

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