Find object in array of nested objects

Question

const inventory = [
  { name: { vegetable: 'carrot' }, quantity: 2 },
  { name: { meat: 'pork' }, quantity: 0 },
  { name: { fruit: 'cherries' }, quantity: 5 },
];

const result = inventory.find(name => name === { fruit: 'cherries' });
console.log(result);

I have an array of nested objects and I'm trying to find out if there is one including the { fruit: 'cherries' } object but I get undefined as a result.

So I guess you can't pass an object as a search parameter?

You can't compare objects like that, only compare references or primitive values. — Hao Wu
– Hao Wu, Commented Feb 7, 2020 at 7:27
As Hao Wu commented two objects can't be compared with strict equality { fruit : 'cherries' } === { fruit : 'cherries'} will return false. So you get undefined. — Ankit
– Ankit, Commented Feb 7, 2020 at 8:28

kn_pavan · Accepted Answer · 2020-02-07 07:35:45Z

1

Please explore Sbtree module or TyrDb module (TyrDb is a wrapper on top of Sbtree with abstracted API). These libraries let you search nested element.

answered Feb 7, 2020 at 7:35

kn_pavan

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StepUp · Accepted Answer · 2020-02-07 08:28:40Z

1

You need to write full path to the object and access to object through . sign:

const result = inventory.find(name => name.name.fruit === 'cherries');

An example:

const inventory = [
    { name: { vegetable: 'carrot' }, quantity: 2 },
    { name: { meat: 'pork' }, quantity: 0 },
    { name: { fruit: 'cherries' }, quantity: 5 },
  ];
  
  const result = inventory.find(name => name.name.fruit === 'cherries');
  console.log(result);

It will be better seen in debugger what there is actual path to your properties of object:

const result = inventory.find(name => {
    if(name.name.fruit === 'cherries')
        return name;
    return;
});
console.log(result);

edited Feb 7, 2020 at 8:28

answered Feb 7, 2020 at 7:29

StepUp

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Comments

Mihai Alexandru-Ionut · Accepted Answer · 2020-02-07 07:28:42Z

0

You can't compare objects because they have different references. One way could be using destructuring and just simply access the fruit property in order to compare it with a given value.

const inventory = [
  { name: { vegetable: 'carrot' }, quantity: 2 },
  { name: { meat: 'pork' }, quantity: 0 },
  { name: { fruit: 'cherries' }, quantity: 5 },
];

const result = inventory.find(({name}) => name.fruit == "cherries");
console.log(result);

answered Feb 7, 2020 at 7:28

Mihai Alexandru-Ionut

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Comments

Bonovski · Accepted Answer · 2020-02-07 21:14:10Z

Thanks for all the suggestions. I think I found a solution to my problem.

I used array.map to create a new array consisting of only the name objects. Then I used JSON.stringify on selectedOption and on the elements in the new array to find a match and/or index.

There is probably a better way of doing it but this is working OK. Feel free to point out any potential flaws in my approach.

const selectedOption = {fruit_red: "cherries", fruit_green: "kiwi"}
    
    const inventory = [
      { name: { vegetable: 'carrot' }, quantity: 2 },
      { name: { meat: 'pork' }, quantity: 0 },
      { name: { fruit_red: 'cherries', fruit_green: 'kiwi' }, quantity: 5 },
      { name: { fruit_red: 'cherries', fruit_green: 'apple' }, quantity: 3 },
    ];
    
    const names = inventory.map(item => item.name)
    
    const resultIndex = names.findIndex(name => JSON.stringify(name) === JSON.stringify(selectedOption));
    console.log(resultIndex)
    
    const result = names.find(name => JSON.stringify(name) === JSON.stringify(selectedOption));
    console.log(result)
    console.log(inventory[resultIndex])

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