Return matching item from within nested array of objects

Question

I have array of grouped by scheduledOn data as below

[{
scheduledOn: "2020-02-05T00:00:00"
matches:
{id: 1, homeTeamName: "BLUE", homeTeamId: 1, homeScore: 1, awayTeamName: "Red", awayTeamId: 2, …}
{id: 2,homeTeamName: "Red", homeTeamId: 2, homeScore: 1, awayTeamName: "Yellow", awayTeamId: 3, …}
},
{
scheduledOn: "2020-01-06T00:00:00"
matches:
0: {id:3, homeTeamName: "BLUE", homeTeamId: 1, homeScore: 0, awayTeamName: "Yellow", awayTeamId: 3, …}
}]

I would like to return one matches object(Not an array) that match with selected id

Possible Solution I tried 1:

matches.map(match => match.matches
              .find(m => m.id === selectedId))

this returns:

 [{

    id: 1, homeTeamName: "BLUE", homeTeamId: 1, homeScore: 1, awayTeamName: "Red", awayTeamId: 2, …
    }]

but I want this to be just an object instead of array.

Possible Solution I tried 2:

matches.map(match => match.matches
              .filter(m => m.id === selectedId))
              .map(match => console.log(match

)

this returns:

 [
    {id: 1, homeTeamName: "BLUE", homeTeamId: 1, homeScore: 1, awayTeamName: "Red", awayTeamId: 2, …}
    ]

But this also returns as array.

Is there a way that I can have matched id object instead of array?

Thanks for all your help

Zohaib Ijaz · Accepted Answer · 2020-02-06 17:22:47Z

2

You use find() twice

const matches = [{
scheduledOn: "2020-02-05T00:00:00",
matches:[
{id: 1, homeTeamName: "BLUE", homeTeamId: 1, homeScore: 1, awayTeamName: "Red", awayTeamId: 2 },
{id: 2,homeTeamName: "Red", homeTeamId: 2, homeScore: 1, awayTeamName: "Yellow", awayTeamId: 3 }]
},
{
scheduledOn: "2020-01-06T00:00:00",
matches:[{id:3, homeTeamName: "BLUE", homeTeamId: 1, homeScore: 0, awayTeamName: "Yellow", awayTeamId: 3 }]
}];


const selectedId =  3;
const required = matches.find(match => 
                  match.matches.find(m => m.id === selectedId));
console.log(required);

   // if you wanted nested object, add another `.find()`
   console.log(required .matches.find(m => m.id === selectedId));

edited Feb 6, 2020 at 17:22

answered Feb 6, 2020 at 17:09

Zohaib Ijaz

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6 Comments

Jake Kwon Over a year ago

It returns {scheduledOn: "2020-02-05T00:00:00", matches: Array(2)} scheduledOn: "2020-02-05T00:00:00" matches: 0: {homeTeamName: "BLUE", homeTeamId: 1, homeScore: 1, awayTeamName: "Red", awayTeamId: 2, …} 1: {homeTeamName: "Red", homeTeamId: 2, homeScore: 1, awayTeamName:

Jake Kwon Over a year ago

i want only match data

Zohaib Ijaz Over a year ago

This is what you asked in 1st version of question

Jake Kwon Over a year ago

I think I did not put a question right. Is there a way that I can only find one matches object?

Zohaib Ijaz Over a year ago

@JakeKwon I added what you wanted. See the updated answer

|

Yevhen Horbunkov · Accepted Answer · 2020-02-06 18:06:11Z

You may flatten all matches properties into single array with flatMap() and search through it:

const src = [{"scheduledOn":"2020-02-05T00:00:00","matches":[{"id":1,"homeTeamName":"BLUE","homeTeamId":1,"homeScore":1,"awayTeamName":"Red","awayTeamId":2},{"id":2,"homeTeamName":"Red","homeTeamId":2,"homeScore":1,"awayTeamName":"Yellow","awayTeamId":3}]},{"scheduledOn":"2020-01-06T00:00:00","matches":[{"id":3,"homeTeamName":"BLUE","homeTeamId":1,"homeScore":0,"awayTeamName":"Yellow","awayTeamId":3}]}],
      itemWithId2 = src.flatMap(({matches}) => matches).find(({id}) => id==2)
      
console.log(itemWithId2)

Though, you should bear in mind, it may fail (just like so many other cool things) in Microsoft browsers (at least until IE passed away).

If that is the case, you may use arr.reduce((r,{matches}) => r.concat(matches), []) instead of flatMap().

Though, when dealing with large arrays, nested finds, suggested by @Zohaibljaz would be more performant.

My implementation of it would be something unacceptably non-readable:

const src = [{"scheduledOn":"2020-02-05T00:00:00","matches":[{"id":1,"homeTeamName":"BLUE","homeTeamId":1,"homeScore":1,"awayTeamName":"Red","awayTeamId":2},{"id":2,"homeTeamName":"Red","homeTeamId":2,"homeScore":1,"awayTeamName":"Yellow","awayTeamId":3}]},{"scheduledOn":"2020-01-06T00:00:00","matches":[{"id":3,"homeTeamName":"BLUE","homeTeamId":1,"homeScore":0,"awayTeamName":"Yellow","awayTeamId":3}]}]

let objectHavingIdOf2 = {}

src.find(({matches}) => 
  matches.find(item => 
    item.id == 2 ? 
    (objectHavingIdOf2 = item, true) :
    false))
    
console.log(objectHavingIdOf2)

You're most welcome. Take a look at extended version of my answer if performance does matter to process large arrays.

Anuj Shah · Accepted Answer · 2020-02-06 17:06:40Z

1

Here's a simple recursive function to help you with:

function findById(arr, id) {
    return arr.find(a => {
        if (a.matches && a.matches.length > 0) {
            return a.id === id ? true : findById(a.matches, id)
        } else {
            return a.id === id
        }
    })
}

// call this method with your data
findById(data, 1)

answered Feb 6, 2020 at 17:06

Anuj Shah

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