Javascript Array Specific Order

Question

I have an array of js object

const name = 'Levi'
var data = [ 
{ firstname: 'Levi', food: 'apple'     },
{ firstname: 'Eren', food: 'orange'   },
{ firstname: 'Levi', food: 'grapes' },
{ firstname: 'Miks', food: 'banana' }
];

How can I sort the firstname and prioritized (Levi) as on top.

Expected Output:

[{firstname: Levi, food: apple},
{ firstname: Levi, food: grapes },
{ firstname: Eren, food: orange   },
{ firstname: Miks, food: banana}]

I used this code

this.data.sort((a, b) => (a.firstname > name) ? 1 : ((name> a.firstname) ? -1 : 0));

Step 1: implement sorting you want but without prioritisation. When you have it - update the question. — zerkms
– zerkms, Commented Jan 31, 2020 at 3:45
this.data.sort((a, b) => (a.firstname === name) ? -1 : (b.firstname === name) ? 1 : a.firstname.localeCompare(b.firstname)); — Jaromanda X
– Jaromanda X, Commented Jan 31, 2020 at 3:47

hoangdv · Accepted Answer · 2020-01-31 04:05:05Z

The first check both a and b firstname are name or not, if true, do nothing.

Next, check a firstname or b firstname is name, if true, find who has firstname is name, and swap a and b or not.

Finally, check with alphabetical order rule.

const name = 'Levi'
var data = [
  { firstname: 'Levi', food: 'apple' },
  { firstname: 'Eren', food: 'orange' },
  { firstname: 'Levi', food: 'grapes' },
  { firstname: 'Miks', food: 'banana' },
  { firstname: 'AMiks', food: 'mango' }
];

const sorted = data.sort((a, b) => {
  if (a.firstname === name && b.firstname === name) {
    return 0;
  }
  if (a.firstname === name || b.firstname === name) {
    return a.firstname === name ? -1 : 1;
  }
  return a.firstname.localeCompare(b.firstname);
});

console.log(sorted);

Output:

[ { firstname: 'Levi', food: 'apple' },
  { firstname: 'Levi', food: 'grapes' },
  { firstname: 'AMiks', food: 'banana' },
  { firstname: 'Eren', food: 'orange' },
  { firstname: 'Miks', food: 'banana' } ]

Siva Kondapi Venkata · Accepted Answer · 2020-01-31 04:17:37Z

0

If a and b firstnames are equal to name, then sort on their food. If a firstname is name, then prioritize.

const name = "Levi";
var data = [
  { firstname: "Levi", food: "apple" },
  { firstname: "Eren", food: "orange" },
  { firstname: "Levi", food: "grapes" },
  { firstname: "Miks", food: "banana" }
];

const sortAsc = (a, b) => {
  if (b > a) {
    return -1;
  }
  if (a > b) {
    return 1;
  }
  return 0;
};

data.sort((a, b) => {
  if (a.firstname === name && b.firstname === name) {
    return sortAsc(a.food, b.food);;
  }
  if (a.firstname === name) {
    return -1;
  }
});


console.log(data);

answered Jan 31, 2020 at 4:17

Siva Kondapi Venkata

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