I wat to traverse over the nested list below, find 1 then print index of that list.
my_list = [['Hello', 'World','!'],[1, 3, 'Test', 5, 7],[2, 4]]
for item in range(len(my_list)):
for item2 in range(len(my_list[item])):
output = my_list[item][item2]
if output == 1:
print('the index of 1 is [%d][%d] ' % (item.item2))
The loops above returned AttributeError: 'int' object has no attribute 'item2'
Can anyone tell me how to fix it? Thank you for the help!
Everything seems fine in your code, just make the string formatter a tuple. Modify the last line of your code to this below:
print('the index of 1 is [%d][%d] ' % (item,item2))
I have used enumerate on the nested list to use both the index of the item in the list and the respective list item.
To find the index of an item use the list_name.index(value) method.
Use in to check the membership i.e. to check if a value is in the list.
my_list = [['Hello', 'World','!'],[1, 3, 'Test', 5, 7],[2, 4]]
for i, item in enumerate(my_list):
if 1 in item:
print('Index of 1 is [{}][{}]'.format(i,item.index(1)))
Output:
i1, i2 would be a less confusing naming choice for the loop variablesfor i in my_list:
if 1 in i:
print(str(i.index(1)) + "th element of " + str(i))
This outputs
0th element of [1, 3, 'Test', 5, 7]
