How can I covert each string of an array to be an Object in the array in TypeScript?

Question

I am having this array.

const array = ["Pizza","Pasta","Choco"];

I want to do this:

const array = [["Pizza"],["Pasta"],["Choco"]];

How can I do this?

You can use .map() to map each element to an array

Nick Parsons
– Nick Parsons

2020-01-23 09:13:27 +00:00
Commented Jan 23, 2020 at 9:13 — Nick Parsons
– Nick Parsons, Commented Jan 23, 2020 at 9:13
@NickParsons can u write it?

Kathrine Hanson
– Kathrine Hanson

2020-01-23 09:19:55 +00:00
Commented Jan 23, 2020 at 9:19 — Kathrine Hanson
– Kathrine Hanson, Commented Jan 23, 2020 at 9:19

Nick Parsons · Accepted Answer · 2020-01-23 09:21:40Z

1

Using Array.prototype.map(), you can provide a function (str => [str]) which wraps each of your string food elements in an array. This will give you a new array, which contains all your elements nested within their own arrays.

See example below:

const array = ["Pizza","Pasta","Choco"];
const result = array.map(str => [str]);
console.log(result);

answered Jan 23, 2020 at 9:21

Nick Parsons

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