functions with if else statement to prompt javascript

Question

So I have been racking my brain why this doesn't work, I am sure that I am over thinking it but after googling for a few hours I just can't find it.

So the main thing I am trying is to create a JavaScript function “legs” which takes animal Object and returns some custom message (String) if the animal has 0 legs, 2, 4, and one message for others.

My attempt:

var animal = prompt("Type in an animal")

function legs(animal){

    if(animal == 'fish'){
        return "no legs";
    }else if(animal == 'Tiger'){
        return "4 legs";
    }else if(animal == 'kangaroo'){
        return "2 legs";
    }else { 
        return "I don't know";
        }
}

What am I doing wrong?

^... leads to even a more fundamental question: Where are you expecting to see the return value of the function? — Teemu
– Teemu, Commented Jan 8, 2020 at 6:18
Not related, but I can't help myself: kangaroos have 4 legs. Just like we, humans. — Gerardo Furtado
– Gerardo Furtado, Commented Jan 8, 2020 at 6:20
@GerardoFurtado Bah, the joke doesn't work in english, in my native language "primate" is "a creature with hands" ... — Teemu
– Teemu, Commented Jan 8, 2020 at 6:26

Sudhir Ojha · Accepted Answer · 2020-01-08 06:20:34Z

1

You need to call legs function like legs(animal)

var animal = prompt("Type in an animal")

function legs(animal){

    if(animal == 'fish'){
        return "no legs";
    }else if(animal == 'Tiger'){
        return "4 legs";
    }else if(animal == 'kangaroo'){
        return "2 legs";
    }else { 
        return "I don't know";
        }
}
console.log(legs(animal));

answered Jan 8, 2020 at 6:20

Sudhir Ojha

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1 Comment

JavaJunior Over a year ago

Ahh, I see what I did wrong. Thank you for your help. I was overthinking it.

Narendra Chouhan · Accepted Answer · 2020-01-08 06:22:52Z

0

this way you can call the leg() function.

var animal = prompt("Type in an animal")

function legs(animal) {
   if (animal == 'fish') 
      return "no legs";
    else if (animal == 'Tiger') 
      return "4 legs";
    else if (animal == 'kangaroo') 
      return "2 legs";
    else 
      return "I don't know";
}

let result = legs(animal)
console.log(result)

answered Jan 8, 2020 at 6:22

Narendra Chouhan

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Comments

MarterJay · Accepted Answer · 2020-01-08 08:46:36Z

0

Just improving the answer. You to get the answer you need to call the function you have defined. Anyway better (cleaner) if you define it before reaching the interactive part (prompt).

Since you are returning in each scenario you do not need to use an else.

function legs(animal) {
  if (animal == 'fish') 
    return "no legs";
  if (animal == 'Tiger') 
    return "4 legs";
  if (animal == 'kangaroo') 
    return "2 legs";

  return "I don't know";
}

const animal = prompt("Type in an animal");

console.log(legs(animal));

answered Jan 8, 2020 at 8:46

MarterJay

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