Search array and find all the values in array of objects

Question

I have two arrays . One with array of objects and other plain array.

Need to search the first array from all the levels of first array.

let arr1 = [{"LEVEL":1},{"LEVEL":2},{"LEVEL":3,"POSITION":"FCONTROLLER"}, 
            {"LEVEL":4,"POSITION":"RGM"},{"LEVEL":5,"POSITION":"GM"},{"LEVEL":5,"POSITION":"GMH"},{"LEVEL":6},{"LEVEL":7,"POSITION":"EGM"}]

let arr2 = [1,3,5]

Output :

 ["FCONTROLLER","GM","GMH"]

I tried to use reduce method but gives empty result.

  arr2.reduce((a, o) => (o.merged==='1'||o.merged==='3'||o.merged==='5' && a.push(o.value), a), [])

Tiago José · Accepted Answer · 2019-12-21 22:43:19Z

1

You can use indexOf to search for the index of the element level you want in arr2, in case you find, you should return the object, for example :

 let arr1 = [{"LEVEL":1},{"LEVEL":2},{"LEVEL":3,"POSITION":"FCONTROLLER"}, 
            {"LEVEL":4,"POSITION":"RGM"},{"LEVEL":5,"POSITION":"GM"},{"LEVEL":5,"POSITION":"GMH"},{"LEVEL":6},{"LEVEL":7,"POSITION":"EGM"}]

 let arr2 = [1,3,5]

const output =arr1.filter((item) => {
  return arr2.indexOf(item.LEVEL) !== -1
});

It will return every object that object.LEVEL is in arr2.

answered Dec 21, 2019 at 22:43

Tiago José

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2 Comments

Mani Over a year ago

But I do not want LEVEL 1 as it doesnt have position

Tiago José Over a year ago

You can use : return (arr2.indeOf(item.LEVEL) !== -1) && (item.POSITION)

Ori Drori · Accepted Answer · 2019-12-21 22:37:07Z

1

While reducing arr1, check if the current object has a POSITION value, and if its LEVEL is included in arr2. If both are true push it to the accumulator:

const arr1 = [{"LEVEL":1},{"LEVEL":2},{"LEVEL":3,"POSITION":"FCONTROLLER"}, 
            {"LEVEL":4,"POSITION":"RGM"},{"LEVEL":5,"POSITION":"GM"},{"LEVEL":5,"POSITION":"GMH"},{"LEVEL":6},{"LEVEL":7,"POSITION":"EGM"}]

const arr2 = [1,3,5]

const result = arr1.reduce((r, o) => {
  if(o.POSITION && arr2.includes(o.LEVEL)) {
    r.push(o.POSITION)
  }
  
  return r
}, [])

console.log(result)

answered Dec 21, 2019 at 22:37

Ori Drori

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