Generating random integer JavaScript

Question

I want to generate a random integer. When I enter a number in a textbox and call the function by clicking on a button, it says "The number was undefined", instead of giving the value of the generated number. Here is my code:

function getRandomInt(min, max){
    return Math.floor(Math.random(max-min+1)+min);
}

var array=[];
var integer=getRandomInt(1,100);
var broj=array[integer];

In your current code, array is empty, so array[integer] will always be undefined, no matter the value returned by getRandomInt — Calvin Nunes
– Calvin Nunes, Commented Nov 18, 2019 at 13:59

Jadli · Accepted Answer · 2019-11-18 14:23:16Z

1

function getRandomInt(min, max) {
  return Math.random() * (max - min) + min;
}
var array=[];
function genRateNumber(){

var integer=Math.floor(getRandomInt(1,100));
array.push(integer)
console.log('array :'+array)
console.log('current Genrated  Value:'+integer)
}

<button onclick="genRateNumber()">genrate number</button>

edited Nov 18, 2019 at 14:23

answered Nov 18, 2019 at 14:17

Jadli

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StepUp · Accepted Answer · 2019-11-18 14:04:10Z

0

Your array is empty. You need to push your generated value:

function getRandomInt(min, max){
    return Math.floor(Math.random(max-min+1)+min);
}

let array=[]; // here array is empty
let integer=getRandomInt(1,100);
let broj=array.push(integer);
console.log(integer);

answered Nov 18, 2019 at 14:04

StepUp

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Comments

rkmsnc · Accepted Answer · 2019-11-18 14:11:19Z

0

function getRandomInt(min, max){
    return Math.floor(Math.random() * (max - min)) + min;
}
var integer1=getRandomInt(1,100);
console.log(integer1);

answered Nov 18, 2019 at 14:11

rkmsnc

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