How to change all characters of a string in Javascript with replace() method?

Question

I am trying to change the characters of a string using for loop. My aim is to change each character with the following one. For example a should be converted to b, b is to c and finally z to a, etc. I have written the following code but it doesn't work.

function LetterChanges(str) { 
    var char = "abcdefghijklmnoprstuvyz";
    for(var i = 0; i < char.length; i++) {
        var newStr = str.replace(/char[i]/gi, char[i + 1]); // the problem is here 
    }
    return newStr; 
}
   
// keep this function call here 
console.log(LetterChanges(readline()));

You can use the RegExp constructor stackoverflow.com/questions/494035/… but you have an issue at the end of your loop, (i+1 won't be a valid index anymore), plus if you fix that, you will replace everything with z. — ASDFGerte
– ASDFGerte, Commented Nov 8, 2019 at 22:43

Nina Scholz · Accepted Answer · 2019-11-08 22:45:37Z

4

You could find a letter and replace with a function.

function LetterChanges(str) {
    var char = "abcdefghijklmnoprstuvyz";
    return str.replace(/[a-z]/gi, c => char[char.indexOf(c) + 1] || char[0]);
}

console.log(LetterChanges('foobar'));

answered Nov 8, 2019 at 22:45

Nina Scholz

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Andrew-io · Accepted Answer · 2019-11-09 00:27:23Z

0

in a single row:

const LetterChanges = (str=‘’) => String.fromCharCode(...[...str].map(c => c.charCodeAt(0) +1));

or if you prefer:

function LetterChanges(str = ‘’) {
    return String.fromCharCode(...[...str].map(c => c.charCodeAt(0) +1));
}

edited Nov 9, 2019 at 0:27

answered Nov 8, 2019 at 23:38

Andrew-io

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