2048 game in Python

Question

As a beginner I started to code a 2048 game. I made the matrix and filled it with 0's. Then I wanted to write a function which loops trough the whole matrix and find all the 0 values. Then save the coordinates of the 0 values and later replace them with 2 or 4 values. I made a random variable to choose beetween 2 or 4. The problem is, that i don't really know how to push the x and y coordinates of the 0 values to and array and then read them.




table = [[0, 0, 0, 0],
         [0, 0, 0, 0],
         [0, 0, 0, 0],
         [0, 0, 0, 0]]


options = []



def saveOptions(i, j):
     options.append([{i , j}])
     return options




def optionsReaderandAdder(options):
    if len(options) > 0:
        spot = random.random(options)
        r = random.randint(0, 1)
        if r > 0.5:
            table  <-------- THIS IS THE LINE WHERE I WOULD LIKE TO CHANGE THE VALUE OF THE 0 TO 2 OR 4.










def optionsFinder():
    for i in range(4):
        for j in range(4):
            if table[i][j] == 0:
                saveOptions(i, j)

    optionsReaderandAdder(options)


addNumber()

print('\n'.join([''.join(['{:4}'.format(item) for item in row])
                 for row in table]))

{i , j} is an unordered set. You probably want a tuple, (i , j). Unless 2048 is symmetrical, I don't know. — Open AI - Opting Out
– Open AI - Opting Out, Commented Oct 15, 2019 at 12:21

Open AI - Opting Out · Accepted Answer · 2019-10-15 12:27:11Z

2

You can iterate over the rows and columns of the table:

for row in table:
    for element in row:
        if element == 0:
             # now what?

We don't know what the coordinate is.

Python has a useful function named enumerate. We can iterate the same way as previously, but we also get the index, or position into the array.

zeroes = []

for i, row in enumerate(table):
    for j, element in enumerate(row):
        if element == 0:
             zeroes.append((i, j))

We can then set the values, for example all to 2:

for i, j in zeroes:
    table[i][j] = 2

Your random code looks fine.

answered Oct 15, 2019 at 12:27

Open AI - Opting Out

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1 Comment

D.Tomi Over a year ago

Thank you very much! Gonna look at it home

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