Parse out a URL query argument in javascript

Question

I'm using javascript and need to parse out a query argument that is a URL:

/folderone/two?link=http%3A%2F%2Fwww.cooldomainname.com

This is doubly hard because I not only need to parse out the query argument "link", but once I have that, the "://" seems to have been turned into: "%3A%2F%2F"

I got so far as to do this:

url.replace(/^.*\=/, '');

Which left me with:

http%3A%2F%2Fwww.cooldomainname.com

But now I still need to handle these "%3A%2F%2F" I could just do a find and replace, but I feel like there must be some type of library that I should be using to "de-URLify" query arguments?

please add a javascript tag

ianace
– ianace

2011-04-25 01:15:21 +00:00
Commented Apr 25, 2011 at 1:15 — ianace
– ianace, Commented Apr 25, 2011 at 1:15

Wayne · Accepted Answer · 2011-04-25 01:16:38Z

1

Use:

decodeURIComponent("http%3A%2F%2Fwww.cooldomainname.com");

Output:

"http://www.cooldomainname.com"

Note also that I think split is a more natural choice than replace:

"/folderone/two?link=http%3A%2F%2Fwww.cooldomainname.com".split("=")[1]

(It's assumed that your input string has just the one parameter.)

answered Apr 25, 2011 at 1:16

Wayne

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