Looping a array in javascript - in an order [duplicate]

Question

I have the following loop in javascript array A

[
    {
    "key1": "value121212",
    "booleankey": false,
    },
    {
    "key1": "value143434",
    "booleankey": false,
    },
    {
    "key1": "value1454545",
    "booleankey": true,
    }
]

I need to loop the above array A and create another array B which includes booleankey, Requirement is, when i create the new array B, the entry with "booleankey": true, should come first. Initial array A can have the booleankey as true as the last entry,

How can i make sure to get the new array B with booleankey true always on the first ? This is how arrayB is created:

createArrayB(entry) {
    arrayA.map((entry) => {
            return  {
                newkey: entry.key1,
                newbooleankey: entry.booleankey,
            }
        });

Sort the array before you map over it? After you map over it? — jonrsharpe
– jonrsharpe, Commented Jul 30, 2019 at 11:12
as @jonrsharpe said, just sort it, and B is what you get as an output — Ionut Ardelean
– Ionut Ardelean, Commented Jul 30, 2019 at 11:14

Nina Scholz · Accepted Answer · 2019-07-30 11:15:10Z

0

You could sort by the boolean key with the delta of it. This moves all true property to top.

var array = [{ key1: "value121212", booleankey: false }, { key1: "value143434", booleankey: false }, { key1: "value1454545", booleankey: true }];

array.sort((a, b) => b.booleankey - a.booleankey);

console.log(array);

answered Jul 30, 2019 at 11:15

Nina Scholz

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