unix bash shell script writing

Question

How to write a bash shell script that accepts 5 different integer values as command line arguments and displays the smallest, the largest and the middle argument. the script uses: An if statement. The if statement should give an error message if the number of arguments is not exactly 5 and then it executes the exit command to end the script.

A push in the right direction or something would greatly be appreciated. thanks

Have you started this exercise yourself? With which parts of the script are you struggling? — johnsyweb
– johnsyweb, Commented Apr 16, 2011 at 0:50

johnsyweb · Accepted Answer · 2011-04-16 01:00:49Z

2

Here's a starter for you, giving you all of the constructs you'll need but without doing the exercise for you...

#!/usr/bin/env bash

if (( ${#@} == 5 )); then
    echo "Correct number of arguments, I'll now play with ${@}, starting with $1 and ending with $5..."
elif (( ${#@} < 5 )); then
    echo $(( 5 - ${#@} )) " more arguments needed."
elif (( ${#@} > 5 )); then
    echo $(( ${#@} - 5 )) " fewer arguments needed."
fi

If you run through the Bash Scripting Tutorial, you should be able to do this in no time at all!

answered Apr 16, 2011 at 1:00

johnsyweb

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