I want to display checked checkbox which are stored as values in a mysql database.
For now the table stores the value of the checkbox being checked in the database. The header and first column are fetched from three different tables in the database. While the values of the checked check-boxes gets saved in a same table.
Here's the code for inserting the data.
$active = "CourseReport";
require_once 'pages/header.php';
require_once './functions/schema-functions.php';
require_once './functions/report-functions.php';
$course = Schema::getCourseReport();
$objective = Schema::getObjective();
$goals = Schema::getGoals();
$mainobj = Schema::getMainObjectives();
$subobj = Schema::getSubObjectives();
?>
<form id="addReport" action ='./functions/report-functions.php' method="post">
<table id="table1" class="table table-hover">
<thead>
<?php
echo '<tr><th>Goals</th>';
for ($i = 0; $i < count($course); $i++) {
echo '<th id = "rotate1">'. $course[$i]->commonName . '</th>';
}
echo '</tr>';
?>
</thead>
<tbody>
<?php
for ($y = 0; $y < count($goals); $y++) {
echo '<tr class="clickable"><th class="toggle">Goal#'.$goals[$y]['GoalId'].':'." " .' '.$goals[$y]['Goals'].'</th>
</tr>';
?>
<?php
for( $z = 0; $z < count($mainobj); $z++){
if($mainobj[$z]['GoalId'] == $goals[$y]['GoalId']) {
echo '<tr class="expander"><th class=row-header>Objective#'.$mainobj[$z]['MainObjId'].':'." ".' '.$mainobj[$z]['MainObjectives'].'</th>
</tr>';
?>
<?php
for ($j = 0; $j< count($subobj); $j++) {
if($mainobj[$z]['MainObjId'] == $subobj[$j]['MainObjId']){
echo '<tr class="expander"><td class=row-header>'.$subobj[$j]['SubObjId'].' ) '.$subobj[$j]['SubObjectives'].' </td>';
for ($x = 0; $x < count($course); $x++) {
echo "<td><input name='check[]' type=checkbox value=c".$course[$x]->courseId."-o".$subobj[$j]['SubObjId']." id=checked></td>";
}
echo '</tr>';
}
}
}
}
}
?>
</tbody>
</table>
<button class="button" name= "submit" value= "Submit">Submit</button>
</form>
report-functions.php
if( isset( $_POST['submit'], $_POST['check'] ) ){
try{
require_once 'db-connect.php';
$conn = DatabaseConnection::getConnection();
$sql= " insert into `Report` (`ColRow`) values (:value) ";
$stmt = $conn->prepare( $sql );
if( $stmt ){
$conn->beginTransaction();
foreach( $_POST['check'] as $index => $value ) {
$result = $stmt->execute( [ ':value' => $value ] );
if( !$result ) {
echo '
<script>
alert("Error, please try submitting again. Error code 1");
window.history.back();
</script>';
}
}
$conn->commit();
echo '<script>
alert("Report was submitted successfully.");
window.location = ".../";
</script>';
}
} catch( Exception $e ){
$conn->rollback();
exit( $e->getMessage() );
}
I expect that once I submit the table, the table should load the same table with the checked checkboxes. I should be able to make the changes and submit the table over and over again.
Please comment if I need to provide any additional information.
<input>element, add anifstatement. If the value in the database is checked, add this to the<input>element:checked="checked". It will therefore be checked, based on the database value.$_POST['check']into theColRowitem in the database. The reverse is also possible. Do a select on the database. If the value forColRowequals the value you are about to print to the html page , then add the checked code on the input element. To go deeper in the explanation, you would have to add a database sample and html output sample to the question?>) to just open a new one on the next line (<?php). Open and close once. Another, to read your code, I put it in an editor and did the indentation again. Helped a lot. Still looking...