There is nested names array with only strings, need to loop through to find how many times each string appears. Since two elements have "bob" resulting function should return 2. How to search for the string even if array is nested?
var names = ["bob", ["steve", "michael", "bob", "chris"]];
function loop(){
/* .... */
}
var result = loop(names, "bob");
console.log(result); // 2
Example
var names = ["bob", ["steve", "michael", "bob", "chris"]];
function loop(names, searchString){
var flattenArray = names.flat(Infinity);
return flattenArray.filter(n => n === searchString).length;
}
var result = loop(names, "bob");
console.log(result); // 2
.flat() is relatively new and not supported by all major browsers (Edge for example). If browser support is needed for Edge/IE, consider implementing a polyfill.You can flatten and filter the array and then just return the length of the filtered array.
const names = ["bob", ["steve", "michael", "bob", "chris"]];
function loop ( arr, name ) {
return arr.flat( Infinity ).filter( el => el === name ).length;
}
const result = loop(names, "bob");
console.log(result); // 2you can use flatMap
var names = ["bob", ["steve", "michael", "bob", "chris"]];
console.log(names.flatMap(el => el === "bob").length)You can simply iterate and determine this way as well:
var names = ["bob", ["steve", "michael", "bob", "chris"]];
var result = 0;
function loop(names,searchElement){
for (var el=0;el<names.length;el++){
if(Array.isArray(names[el])){
for(var elem=0;elem<names[el].length;elem++){
if(names[elem]==searchElement){
result = result + 1;
}
}
}
else{
if(names[el]==searchElement){
result = result + 1;
}
}
}
return result;
}
var results = loop(names, "bob");
console.log(result);
"bob"" - Are you trying to return the total number of"bob"strings, or the total number of elements that contain a"bob"string?