JavaScript compare an array to an object of arrays to see if their values match

Question

I have an array that I'm trying to compare to see if the values in array 1 are in any of the arrays inside an object:

arr1 = [9]

obj1 = {Cards: [8,5], Loans: [], Shares: [0,9,25]}

I'm using JavaScript(ECMAScript 5) to try and do this, all I need is true to be returned if any of the values in arr1 are found inside obj1.

What I've tried:

function arraysEqual(_arr1, _arr2) {
  if (!Array.isArray(_arr1) || !Array.isArray(_arr2) || _arr1.length !== _arr2.length)
    return false;
  var arr1 = _arr1.concat().sort();
  var arr2 = _arr2.concat().sort();
  for (var i = 0; i < arr1.length; i++) {
    if (arr1[i] !== arr2[i])
      return false;
  }
  return true;
}

This however will just test to see if the arrays in specific so I have to call this three times to check the values, even this however will return false when I try:

arraysEqual(arr1, obj1.Shares)

Would like this to be done with one call

what code have you tried? where did you have problems?

Daniel A. White
– Daniel A. White

2019-06-06 18:59:11 +00:00
Commented Jun 6, 2019 at 18:59 — Daniel A. White
– Daniel A. White, Commented Jun 6, 2019 at 18:59

adiga · Accepted Answer · 2019-06-06 19:16:57Z

2

You could check if every item in arr1 is in arr2 using indexOf:

function compare(arr1, arr2) {
  return arr1.every(function(n){
    return arr2.indexOf(n) > -1
  })
}

var arr = [9],
    obj = { Cards: [8,5], Loans: [], Shares: [0,9,25] }

console.log(compare(arr, obj.Shares))
console.log(compare(arr, obj.Cards))

answered Jun 6, 2019 at 19:16

adiga

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Comments

izeke · Accepted Answer · 2019-06-06 19:14:33Z

0

You can use a for...in loop to iterate through the object, then you can use a for loop to iterate through the main array, finally using an array.includes on your secondary array (from the object) to see if any elements from the main array exist in the secondary array

arr1 = [3]
obj1 = {Cards: [8,5], Loans: [], Shares: [0,9,25]};

for (arr2 in obj1)
{
  for (i = 0; i < arr1.length; i++) {
    if (obj1[arr2].includes(arr1[i]))
    {
      console.log('exists');
    }
  }
}

answered Jun 6, 2019 at 19:14

izeke

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Comments

Prince Devadoss · Accepted Answer · 2019-06-06 19:15:59Z

0

Another way of doing is using Array.prototype.some(),

var array = [8,9];
var obj = {o1:[18,99], o2:[19], o3:[8,56]};
var p = array.some((arr) => {
    var ret =  Object.values(obj).find((value) => {
        return value.find((val) => val === arr);
    });
    return ret ? true : false;

});

console.log(p);

answered Jun 6, 2019 at 19:15

Prince Devadoss

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Comments

Paul Bota · Accepted Answer · 2019-06-06 19:27:43Z

0

This one should work:

let arr1 = [9, 8]

let obj1 = {Cards: [8,5], Loans: [], Shares: [0,9,25]}

function check(arr1, obj1) {
  let values = Object.keys(obj1).map((key)=> obj1[key]).reduce((acc, val) => acc.concat(val));

   for(let n of arr1) {
        if(values.indexOf(n) === -1) return false;
      }
   return true;
}
  
console.log(check(arr1, obj1));

edited Jun 6, 2019 at 19:27

answered Jun 6, 2019 at 19:16

Paul Bota

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4 Comments

Charles L. Over a year ago

cant use ES6 with this solution

Paul Bota Over a year ago

this one should be ES5 compatible

IceMetalPunk Over a year ago

@PaulBota Object.values didn't exist in ES5.

Paul Bota Over a year ago

@IceMetalPunk yea you are right, updated it. thank you

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