Array how to sort by mutiple property by Swift?

Question

I want to sort array data by number value like "90 > 80 > 70 ...> 10".
But I don't know how to compare mutiple property.

struct Item {
   let number1: Double
   let number2: Double
   let number3: Double
}

let item1 = Item(number1:0, number2:0, number3:10)
let item2 = Item(number1:20, number2:0, number3:0)
let item3 = Item(number1:0, number2:30, number3:0)
let item4 = Item(number1:0, number2:0, number3:40)
let item5 = Item(number1:0, number2:50, number3:0)
let item6 = Item(number1:60, number2:0, number3:0)
let item7 = Item(number1:0, number2:70, number3:0)
let item8 = Item(number1:0, number2:0, number3:80)
let item9 = Item(number1:0, number2:90, number3:0)

var array:[Item] = [item1, item2, item3, item4, item5, item6, item7, item8, item9]

array = array.sorted { (item, nextItem) -> Bool in {
     item.number3 < nextItem.number3 //how to add item's number2 & number1 into here.
}

This might be what you are looking for: Sort array of objects with multiple criteria. — Martin R
– Martin R, Commented Jun 3, 2019 at 8:28
At present it is unclear what you are asking for. – Is Item(number1:20, number2:0, number3:0) larger or smaller than Item(number1:0, number2:30, number3:0)? And why? — Martin R
– Martin R, Commented Jun 3, 2019 at 8:31
There is no “just sort” without specifying a sorting order – and that is your task. We cannot guess what you are looking for. — Martin R
– Martin R, Commented Jun 3, 2019 at 8:37

RajeshKumar R · Accepted Answer · 2019-06-03 09:06:01Z

1

Sort the elements by the sum of 3 numbers

array = array.sorted { (item, nextItem) -> Bool in
    let itemSum = item.number1 + item.number2 + item.number3
    let nextItemSum = nextItem.number1 + nextItem.number2 + nextItem.number3
    return itemSum > nextItemSum
}

[Item(number1: 0.0, number2: 90.0, number3: 0.0),
Item(number1: 0.0, number2: 0.0, number3: 80.0),
Item(number1: 0.0, number2: 70.0, number3: 0.0),
Item(number1: 60.0, number2: 0.0, number3: 0.0),
Item(number1: 0.0, number2: 50.0, number3: 0.0),
Item(number1: 0.0, number2: 0.0, number3: 40.0),
Item(number1: 0.0, number2: 30.0, number3: 0.0),
Item(number1: 20.0, number2: 0.0, number3: 0.0),
Item(number1: 0.0, number2: 0.0, number3: 10.0)]

edited Jun 3, 2019 at 9:06

answered Jun 3, 2019 at 8:35

RajeshKumar R

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2 Comments

Beginnerrrrrr Over a year ago

I got this Error. The compiler is unable to type-check this expression in reasonable time; try breaking up the expression into distinct sub-expressions

Daniel Klöck Over a year ago

should Item(number1: 20.0, number2: 20.0, number3: 20.0) really be bigger than Item(number1: 50.0, number2: 0.0, number3: 0.0)?

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