pass command line arguments to python interpreter without a script file

Question

I want do start the python interpreter and debug with sys.argv. I do not want to provide a python file. If I provide a file, the interpreter executes the file and finishes.

Is there a way to archive this?

python argA argB
...
>>> import sys
>>> print sys.argv
['argA','argB']

use mock's patch function to replace sys.argv with another list. — hunzter
– hunzter, Commented May 2, 2019 at 10:18

brunns · Accepted Answer · 2019-05-02 10:21:26Z

9

This is pretty much what you want:

$ python - argA argB

The first argument will show up as -, though - think of it as a pseudo script name. I don't think you can get away from that.

answered May 2, 2019 at 10:21

brunns

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1 Comment

Cutton Eye Over a year ago

this might be even better! (does not influence the code I'm debugging if i do copy&paste my "consol-research" into working project!!!)

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