I have two scripts: script1.py and script2.py
script1 has its environment (say, python 2), and script2 has its own environment (say, python 3).
How can I make script 1 invoke script 2, with its corresponding environment?
Thanks
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so, did you solve?Leonardo Miquelutti– Leonardo Miquelutti2020-08-25 18:00:31 +00:00Commented Aug 25, 2020 at 18:00
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@LeonardoMiquelutti no. Had to resort to creating a new process and communicating through a message bus. not a good solution, but a working solution is better the a beautiful nothingGulzar– Gulzar2020-09-24 08:32:38 +00:00Commented Sep 24, 2020 at 8:32
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I had to split my script into 3 parts (python 3, 2, and 3 again) but managed to run them all through a single command line. Totally agree with the beautiful nothing part @Gulzar :)Leonardo Miquelutti– Leonardo Miquelutti2020-09-25 09:12:46 +00:00Commented Sep 25, 2020 at 9:12
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1 Answer
A workaround I can think of right now is os.system used to execute other files.
example:
script1.py
#!/usr/bin/env python3
import os
os.system("script2.py")
and
script2.py
#!/usr/bin/env python2
print "script 2 running..."
print "script 2 running..." is great example since python2.X uses print without parentheses and python3.X uses print() with parentheses
It's important to take note of the shebangs (#!/usr/bin/env python3 and #!/usr/bin/env python2) on both scripts which point to the correct entepreters/env for both scripts
os.system can also be used with arguments, like os.system("script2.py data.txt"), which is great if you want to run another script with arguments.
3 Comments
Gulzar
Will this also work in windows the same way? just specify the relevant path in the start of each script?
michael_heath
@Gulzar Possible with Python Launcher for Windows.
sassy_rog
@Gulzar it should be