lodash - remove array of object by it value

Question

Using lodah - how to remove the object by it's value?

here is my try:

var array = ['Education', 'Medicine'];

values = [
    {
      "Category":"Medicine"
    },

    {
      "Category":"Medicine"
    },
    {
      "Category":"Development"
    },
    {
      "Category":"Education"
    }
  ]

  const x = _.without(values, array);

console.log(x); expected value is :

values = [{
  "Category":"Development"
},]

Ori Drori · Accepted Answer · 2019-04-26 09:42:06Z

1

You can use _.differenceWith() to remove items with a Category that exists in the array.

const array = ['Education', 'Medicine'];

const values = [{"Category":"Medicine"},{"Category":"Medicine"},{"Category":"Development"},{"Category":"Education"}];

const result = _.differenceWith(values, array, (o, category) => o.Category === category);

console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>

answered Apr 26, 2019 at 9:42

Ori Drori

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4 Comments

user2024080 Over a year ago

- how to get the values as included only, opposite of current function? I tried o.Category !== category - but not works

Ori Drori Over a year ago

Use intersectionWith instead of differenceWith.

user2024080 Over a year ago

intersectionWith - is not taking array of values at present it takes one last value as Medicine

Ori Drori Over a year ago

Interesting, it seems like a glitch in intersectionWith. The number of results is limited by the 2nd array. In that case you can use @cocoder's answer with !array.includes().

cocoder · Accepted Answer · 2019-04-26 09:50:28Z

1

Actually, I don't think use lodash is better. You can use es6 to solve it.

result = values.filter(x => array.includes(x.Category));

answered Apr 26, 2019 at 9:50

cocoder

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