Is it possible to catch an error exit code in node.js from shell script?

Question

as the title of the question, here is the scenario.

A shell script file script.sh that does some operations and at some point it requires to launch a node file.

#! /bin/bash

node "$(dirname "$0")/script.js" "$input"

echo "${?}\n"

In the node file script.js there are some controls and in case of error the script return with an error exit code.

process.exit(1)

Is it possible to catch this error exit code in order to let the command to be executed in the shell script script.sh?

Currently the execution is interrupted with this error error Command failed with exit code 1., as expected by the way. But I would like to know if I can on shell script to catch this error and continue to execute the last part of the code echo "${?}\n".

Thanks in advance

As I said, the execution is interrupted so nothing happens in script.sh after calling node "$(dirname "$0")/script.js" "$input" . But I would expect echo to print 1. — axel
– axel, Commented Apr 24, 2019 at 8:00

ZEE · Accepted Answer · 2019-04-24 08:04:43Z

4

You can do something like this in your bash script in case your node script return 1

node "$(dirname "$0")/script.js" "$input"
   echo "Script: $? - Successfull"
if [ $? != 0 ]; then                   
   echo "${?}\n". 1>&2 && exit 1
fi

edited Apr 24, 2019 at 8:04

answered Apr 24, 2019 at 7:58

ZEE

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2 Comments

axel Over a year ago

I've just on my standard output this error => error Command failed with exit code 1. and anything else happens in the script.sh after calling node "$(dirname "$0")/script.js" "$input".

axel Over a year ago

ah, it is because of set -o errexit coming from another shell script that actually calls mine.

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