Python Regex replace part of string

Question

I am trying to replace a specific part of my string. Everytime I have a backslash, followed by a capital letter, I want the backslash to be replaced with a tab. Like in this case:

Hello/My daugher/son

The output should look like

Hello    My daugher/son

I have tried to use re.sub():

for x in a:
    x = re.sub('\/[A-Z]', '\t[A-Z]', x)

But then my output changes into:

Hello    [A-Z]y daugher/son

Which is really not what I want. Is there a better way to tackle this, maybe not in regex?

Pushpesh Kumar Rajwanshi · Accepted Answer · 2019-03-21 16:21:58Z

2

You can replace /(?=[A-Z]) with \t. Notice in Python you don't need to escape / as \/

Check this Python code,

import re 

s = 'Hello/My daugher/son'
print(re.sub(r'/(?=[A-Z])',r'\t',s))

Prints,

Hello   My daugher/son

Alternatively, following the way you were trying to replace, you need to capture the capital letter in a group using /([A-Z]) regex and then replace it with \t\1 to restore what got captured in group1. Check this Python codes,

import re 

s = 'Hello/My daugher/son'
print(re.sub(r'/([A-Z])',r'\t\1',s))

Again prints,

Hello   My daugher/son

edited Mar 21, 2019 at 16:21

answered Mar 21, 2019 at 16:16

Pushpesh Kumar Rajwanshi

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