Initialising an array using different array

Question

I have a code that goes as:-

.....
path = 'path_to_csv_file';
file=open(path, "r")
reader = csv.reader(file)
y=np.empty((7000,1))
j=0
for line in reader:
    y[j]=line[0]
    j+=1

....

targets=np.zeros([7000,1,10])

Now, in the first array of targets, I want the y[0]th index to store 1 (y[0] stores integers from 0-9). For that, I wrote:-

targets[0,0,y[0]]=1

But I get an error:-

IndexError: arrays used as indices must be of integer (or boolean) type

When I print y[0], I get:-

[6.]

as the output. What I think is that it's not an integer, so that's probably the source of my error, but I don't know how to fix it. Any help will be appreciated. Thanks!

Use print(y[0]) and show us results. In general there's nothing wrong in targets=np.zeros([7000,1,10]) and targets[0,0,y[0]]=1. Just hardcode y[0] to try (for example y=[[1,2,3,4,5],[1,2,3,4,5]]). The most likely the error is in reading y from file. — Karls
– Karls, Commented Mar 11, 2019 at 13:59
@Karls I've already shown the result for print(y[0]). It gives me [6.] — Ankit Kumar
– Ankit Kumar, Commented Mar 11, 2019 at 14:00
@Karls It goes like 6,0,0,0....... The answer below works by the way, thanks! — Ankit Kumar
– Ankit Kumar, Commented Mar 11, 2019 at 14:04

denis_lor · Accepted Answer · 2019-03-11 14:00:35Z

1

Have you tried with dtype=int?

y=np.empty((7000,1), dtype=int)
...
targets=np.zeros(([7000,1,10]), dtype=int)

You can check more on the documentation on the usage of numpty.empty and numpty.zeros

answered Mar 11, 2019 at 14:00

denis_lor

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2 Comments

denis_lor Over a year ago

@AnkitKumar In case it helped, mark the answer as accepted so anyone else with the same question can understand the answer worked out

Ankit Kumar Over a year ago

Ya, there's a time limit before which i can't accept it, I was just waiting for that

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