Using Output from Function 1 as Input in Function 2

Question

so I have some code like the following:

def _step_1(a, b, c):
    some codes
    return d, e, f

def _step_2(d, e, f, a, b):
    some codes
    return g

def _run_all(a, b, c):
    g = _step_2(_step_1(a, b, c), a, b)
    return g

And it is telling me that I am missing two arguments "a" and "b". Could someone tell me if I did anything wrong by trying to save some steps? Or there is no way to save steps? I know I can definitely write like this:

def _run_all(a, b, c):
    d, e, f = _step_1(a, b, c)
    g = _step_2(d, e, f, a, b)
    return g

You're only passing three arguments to _step_2(). Even though the result of _step_1(a,b,c) contains three elements, it is itself just a tuple. As @U9-Forward answered, if you're using Python 3, you can automatically unpack that result into its three separate values. — John Gordon
– John Gordon, Commented Mar 1, 2019 at 5:21
Thank you for your explanation! And yes, I am using Python 3, it worked. — Qinao QA Wang
– Qinao QA Wang, Commented Mar 1, 2019 at 5:46

U13-Forward · Accepted Answer · 2019-03-01 05:01:28Z

5

If your version is python 3, use unpacking (*):

def _run_all(a, b, c):
  g = _step_2(*_step_1(a, b, c), a, b)
  return g

answered Mar 1, 2019 at 5:01

U13-Forward

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