How to sort array by two linked fields? JS [duplicate]

Question

There is a simple part of the code where I need to sort an array of objects by the next way (sorting array objects by a prop first and then by the b prop). So the result should look's like:

var a = [
    {
        a: 1,
        b: 2
    },
    {
        a: 1,
        b: 4
    },
    {
        a: 1,
        b: 5
    },
    {
        a: 2,
        b: 1
    },
    {
        a: 2,
        b: 3
    },
    {
        a: 2,
        b: 4
    }
]

But unfortunately, my code below doesn't seem to work well. Could someone help me? Thank you in advance.

var a = [
    {
        a: 2,
        b: 4
    },
    {
        a: 2,
        b: 3
    },
    {
        a: 1,
        b: 2
    },
    {
        a: 1,
        b: 4
    },
    {
        a: 1,
        b: 5
    },
    {
        a: 2,
        b: 1
    }
]

a.sort((first, second) => first.a - second.a && first.b - second.b ? 1 : -1)

console.log(a)

a.sort((first, second) => first.a - second.a || first.b - second.b) — Nina Scholz
– Nina Scholz, Commented Feb 14, 2019 at 17:48

Amardeep Bhowmick · Accepted Answer · 2019-02-14 17:50:28Z

0

You need to check the first property a if they are equal then go for b.

const a = [{"a":2,"b":4},{"a":2,"b":3},{"a":1,"b":2},{"a":1,"b":4},{"a":1,"b":5},{"a":2,"b":1}];

a.sort((obj1 ,obj2) => obj1.a - obj2.a ? obj1.a - obj2.a : obj1.b -obj2.b );
console.log(a);

answered Feb 14, 2019 at 17:50

Amardeep Bhowmick

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