How to find a word(string) in Javascript array?

Question

I need to check if my array has the word

This is my code please help

    var name = ['heine', 'hans'];
    var password = ['12343', '1234'];
    function login() {
    var pos;
        if(name.includes('hans')) {
            console.log("enthält");
            pos = name.indexOf('hans');
            console.log(pos)
            if(password[pos] === '1234') {
                console.log("angemeldet")
            }
        }
      }

consoleout = 6, but why, it must be a 1

If the word hans is in the array, than i need the position from the word in the array

developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/… — Taplar
– Taplar, Commented Feb 11, 2019 at 18:19
Terrible idea, in relation to authentication on the frontend, but from a mental exercise standpoint, you are asking about indexOf() — Taplar
– Taplar, Commented Feb 11, 2019 at 18:22
password[i] === 1234 will however always be false, due to the passwords being strings and the usage of === — Taplar
– Taplar, Commented Feb 11, 2019 at 18:23
It is returning 6 because apparently it's thinking name is a string. Which is very odd. — Taplar
– Taplar, Commented Feb 11, 2019 at 18:35

Mark · Accepted Answer · 2019-02-11 18:42:06Z

2

You might find some() handy for this. It will pass the index into the callback which you can use to find the corresponding value from the passwords array:

function test(name, pw) {
  let names = ["heine", "hans"];
  let passwords = ["12343", "1234"];
  // is there `some` name/pw combinations that matches?
  return names.some((n, index) => name == n && pw == passwords[index])
}

console.log(test("hans", '1234'))   // true
console.log(test("hans", '12345'))  // false
console.log(test("hans", '12343'))  // false

console.log(test("heine", '12343')) // true
console.log(test("mark", '12343'))  // false

edited Feb 11, 2019 at 18:42

answered Feb 11, 2019 at 18:27

Mark

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Comments

epascarello · Accepted Answer · 2019-02-11 19:01:51Z

0

Problem here is name is window.name which is a string..

var name = ['heine', 'hans'];
console.log(window.name, typeof window.name)

var xname = ['heine', 'hans'];
console.log(window.xname, typeof window.xname)

Change your variable to another word that is not reserved if you are in global scope.

answered Feb 11, 2019 at 19:01

epascarello

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Comments

Shidersz · Accepted Answer · 2019-02-11 19:07:34Z

0

In your case, you can also try something like this with findIndex:

const usernames = ['heine', 'hans'];
const passwords = ['12343', '1234'];

function login(user, pass)
{
    let userIdx = usernames.findIndex(x => x === user);

    // On a real application do not give any tip about which is
    // wrong, just return "invalid username or password" on both cases.
    
    if (userIdx < 0)
        return "Invalid username!";

    if (pass !== passwords[userIdx])
        return "Invalid password!";

    return "Login OK!"
}

console.log(login("heine", "12343"));
console.log(login("hans", "lala"));

edited Feb 11, 2019 at 19:07

answered Feb 11, 2019 at 18:59

Shidersz

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Comments

SkillGG · Accepted Answer · 2019-02-12 05:38:08Z

0

You may use this. I am not sure if it is what you want.

let names = ["heine", "hans"];
let password = ["12343", "1234"];
let i, temp;

function log(login, pass) {
    if((i = names.indexOf(login)) !== -1){
        if(password[i] === pass)
            console.log("Logged!");
    }
}

log("hans", "1234")

edited Feb 12, 2019 at 5:38

answered Feb 11, 2019 at 18:29

SkillGG

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2 Comments

Marvin Würtz Over a year ago

i think it need a for-loop, i just add it now an test it

Marvin Würtz Over a year ago

code var name = ["heine", "hans"]; var password = ["12343", "1234"]; var i, temp; function login(login, pass) { console.log("start") for(temp = 0; temp < name.length; temp++) { console.log(temp) if((i = name.indexOf(login)) !== -1){ console.log("name") if(password[temp] === pass) console.log("Logged!"); } } } login("hans", "1234")

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