http get python query key - value

Question

Write a function named "query_string" that doesn't take any parameters. The function will make an HTTPS GET request to the url "https://fury.cse.buffalo.edu/ps-api/a" with a query string containing the key-value pairs x=5, y=4, and z=5. The response from the server will be a JSON string representing an object in the format "{"answer": }" where is a floating point Number. Return the value at the key "answer" as a float

    import urllib.request
    import json

    def query_string():
        response = urllib.request.urlopen("https://fury.cse.buffalo.edu/ps-api/a")
        content_string = response.read().decode()
        content=json.loads(content_string)
        return float(content['answer'])

output: function query_string incorrect on input []

returned: -1.0 expected: 119.99

any idea how i can fix this issue?

You forgot about the "query string containing the key-value pairs x=5, y=4, and z=5" part. — jwodder
– jwodder, Commented Nov 27, 2018 at 18:06
I'm new to python, well coding in general, do i put that on the end after the /a" in the url? — codernoob3232
– codernoob3232, Commented Nov 27, 2018 at 18:07
Yes your url should be like "fury.cse.buffalo.edu/ps-api/a?x=5&y=4&z=5" — viky.pat
– viky.pat, Commented Nov 27, 2018 at 18:12
I tried that , the url you provided response = urllib.request.urlopen("fury.cse.buffalo.edu/ps-api/a?x=5&y=4&z=5") the output said : error on input []: unknown url type: 'fury.cse.buffalo.edu/ps-api/a?x=5&y=4&z=5' — codernoob3232
– codernoob3232, Commented Nov 27, 2018 at 18:16

SuperStew · Accepted Answer · 2018-11-27 18:28:30Z

1

You can do something like this using the requests package. It's super helpful. You can add the query parameters in a dict that gets passed to the params keyword argument

def query_string():
    import requests
    url=r'https://fury.cse.buffalo.edu/ps-api/a'
    payload={
    'x':5,
    'y':4,
    'z':5}
    r=requests.get(url,params=payload)
    j=r.json()
    print(j)

EDIT for urllib

def query_string():
    url=r'https://fury.cse.buffalo.edu/ps-api/a'
    payload={
    'x':5,
    'y':4,
    'z':5}
    url=url+'?'+urllib.parse.urlencode(payload)
    r=urllib.request.urlopen(url).read().decode()
    r=json.loads(r)
    return float(r['answer'])

edited Nov 27, 2018 at 18:28

answered Nov 27, 2018 at 18:11

SuperStew

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3 Comments

codernoob3232 Over a year ago

Yeah I wanted to use requests as the library, but my professor has blocked that, he wants us explicitly to use urllib

SuperStew Over a year ago

@codernoob3232 Well thats super lame, but i made an edit for using only urllib

codernoob3232 Over a year ago

i figured it out on my own but i tested yours as well and it worked, ill upvote it as the answer as well, appreciate your help man.

codernoob3232 · Accepted Answer · 2018-11-27 18:33:40Z

0

import urllib.request
import json

def query_string():
    url = "https://fury.cse.buffalo.edu/ps-api/a"
    url = url + "?x=5&y=4&z=5"
    response = urllib.request.urlopen(url)
    content_string = response.read().decode()
    content=json.loads(content_string)
    return float(content['answer'])

ended up fixing it after a little research

answered Nov 27, 2018 at 18:33

codernoob3232

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