How to convert a Scala Iterable into Java util.List?

Question

I have a written a method in Scala that is using a method written in Java - processSale() method takes util.List<Sale> as a parameter.

But after groupByKey() I'm getting an RDD[(String, Iterable[Sale])]. I've tried to import scala.collection.JavaConverters._ and do SaleParser.processSale(a.asJava).

However it gives me an Iterable[Sale]. How is it possible to convert it into a Java util.List?

val parseSales: RDD[(String, Sale)] = rawSales
      .map(sale => sale.Id -> sale)
      .groupByKey()
      .mapValues(a => SaleParser.processSale(???))

Alexey Romanov · Accepted Answer · 2018-10-10 20:01:23Z

3

a.toSeq.asJava

Note that if this Iterable is actually a Seq, toSeq just returns the same object.

See API doc for the complete list of conversions.

edited Oct 10, 2018 at 20:01

answered Oct 10, 2018 at 17:40

Alexey Romanov

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