Printing list of numbers as an array from for loop Python

Question

With the code below, it prints the value 'phase' one by one. I am trying to print these values as an array outside of for loop.

import math

Period = 6.2

time1 = datafile1[:,0]
magnitude1 = datafile1[:,1]
for i in range(len(time1)):
   print(i,time1[i])
   floor = math.floor((time1[i]-time1[0])/Period)
   phase = ((time1[i]-time1[0])/Period)-floor 
   print (phase)

It is printing like this:

I would like it to print like this:

[0.002, 0.003, 0.004, 0.005]

Please post your datafile1 structure so answerers can offer working and complete code. — ggorlen
– ggorlen, Commented Sep 26, 2018 at 3:31
Add your phases to a list and do something like: print('[' + ', '.join(phases) + ']') — Matt
– Matt, Commented Sep 26, 2018 at 3:32
just take an empty list and append the elements one by one in it by the same for loop . — Ragib Huda
– Ragib Huda, Commented Sep 26, 2018 at 3:36

vash_the_stampede · Accepted Answer · 2018-09-26 03:32:05Z

2

This would be the least modification requirement path to that result

result = []

time1 = datafile1[:,0]
magnitude1 = datafile1[:,1]
for i in range(len(time1)):
   result.append(i,time1[i])
   floor = math.floor((time1[i]-time1[0])/Period)
   phase = ((time1[i]-time1[0])/Period)-floor 
   result.append(phase)

print(result)

answered Sep 26, 2018 at 3:32

vash_the_stampede

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Matt · Accepted Answer · 2018-09-26 03:33:13Z

0

Here I've made it so instead of printing your results, you append them to a list, then print out the full list.

import math

Period = 6.2

time1 = datafile1[:,0]
magnitude1 = datafile1[:,1]

my_list = []
for i in range(len(time1)):
   my_list.append(i,time1[i])
   floor = math.floor((time1[i]-time1[0])/Period)
   phase = ((time1[i]-time1[0])/Period)-floor 
   my_list.append(phase)

print(my_list)

answered Sep 26, 2018 at 3:33

Matt

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Daveedo · Accepted Answer · 2018-09-26 03:33:29Z

0

You can do

import math

Period = 6.2

time1 = datafile1[:,0]
magnitude1 = datafile1[:,1]
list_to_print = []
for i in range(len(time1)):
   print(i,time1[i])
   floor = math.floor((time1[i]-time1[0])/Period)
   phase = ((time1[i]-time1[0])/Period)-floor
   list_to_print.append(phase)
print (list_to_print)

answered Sep 26, 2018 at 3:33

Daveedo

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