Comparing two array objects data and merge as one object into array in javascript?

Question

my arrays :

const create = [{"month":"Jan","createCount":"4"},{"month":"Feb","createCount":"5"}];

const close = [{"month":"Jan","closeCount":"3"},{"month":"Feb","closeCount":"5"}];

I need to merge the arrays objects to comparing month field.

I want my result like this...

const data = [{"month":"Jan","createCount":"4","closeCount":"3"},{"month":"Feb","createCount":"5","closeCount":"5"}];

I tried this code:

const data = [...create, ...close];

but this as merge the two array data only.

please give any solution to me!

Mohammad Usman · Accepted Answer · 2018-09-17 06:52:47Z

3

You can use .map() and Object.assign() methods:

const create = [{"month":"Jan","createCount":"4"}, {"month":"Feb","createCount":"5"}],
      close = [{"month":"Jan","closeCount":"3"}, {"month":"Feb","closeCount":"5"}];

const result = create.map(
    o => Object.assign({}, o, close.find(({month}) => month === o.month))
);

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

answered Sep 17, 2018 at 6:52

Mohammad Usman

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3 Comments

Nikhil Aggarwal Over a year ago

In my opinion - Using find within map function is going to hit the performance

Mohammad Usman Over a year ago

@NikhilAggarwal May be but it depends on the data in arrays also.

Nikhil Aggarwal Over a year ago

Irrespective of the data, performance will be less. However, smaller data set will have less impact may be negligible.

Nikhil Aggarwal · Accepted Answer · 2018-09-17 07:00:18Z

1

Assuming that there will be no such entry in create array that does not exists in close array and vice-versa

Try following using Array.reduce, Array.map and Object.assign

const create = [{"month":"Jan","createCount":"4"},{"month":"Feb","createCount":"5"}];

const close = [{"month":"Jan","closeCount":"3"},{"month":"Feb","closeCount":"5"}];

// Create an object with key as month and createCount as value
let obj = create.reduce((a, o) => Object.assign(a, {[o.month]: o.createCount}), {});

// Iterate over close array and add createCount from obj
let result = close.map(o => ({...o, createCount : obj[o.month]}));
console.log(result);

edited Sep 17, 2018 at 7:00

answered Sep 17, 2018 at 6:51

Nikhil Aggarwal

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Comments

Uttam Ughareja · Accepted Answer · 2018-09-17 07:03:05Z

0

simply using for in

const create = [{ "month": "Jan", "createCount": "4" }, { "month": "Feb", "createCount": "5" }];
const close = [{ "month": "Jan", "closeCount": "3" }, { "month": "Feb", "closeCount": "5" }];
for (var i in create) {
    var item = create[i];
    item.closeCount = close.find(x => x.month == item.month).closeCount;
}
console.log(create);

answered Sep 17, 2018 at 7:03

Uttam Ughareja

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Comments

arunsakthivel96 · Accepted Answer · 2018-09-17 07:31:37Z

0

Here I have added some Sample please refer that code

const create = [{"month":"Jan","createCount":"4"},{"month":"Feb","createCount":"5"}];
const close = [{"month":"Jan","closeCount":"3"},{"month":"Feb","closeCount":"5"}];
console.log(create.length);

    for(var data = 0 ; data < create.length ; data++){ 
    var datas = []
    if(create[data].month == close[data].month){ 
        datas=Object.assign(create[data],close[data]);console.log(create[data]);
    }
}

answered Sep 17, 2018 at 7:31

arunsakthivel96

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