This function is able to search for a string in an array:
public checkElement( array ) {
for(var i = 0 ; i< array.length; i++) {
if( array[i] == 'some_string' ) {
return true;
}
}
}
How can i use array of arrays in the for loop? I want to pass this to a function that search a string with if condition.
Example input:
array[['one','two'],['three','four'],['five','six']].
You can try the "find" method instead
let arr = [['one','two'],['three','four'],['five','six']];
function searchInMultiDim(str) {
return arr.find(t => { return t.find(i => i === str)}) && true;
}
searchInMultiDim('one');
This is a recursive solution that checks if an item is an array, and if it is searches it for the string. It can handle multiple levels of nested arrays.
function checkElement(array, str) {
var item;
for (var i = 0; i < array.length; i++) {
item = array[i];
if (item === str || Array.isArray(item) && checkElement(item, str)) {
return true;
}
}
return false;
}
var arr = [['one','two'],['three','four'],['five','six']];
console.log(checkElement(arr, 'four')); // true
console.log(checkElement(arr, 'seven')); // falseAnd the same idea using Array.find():
const checkElement = (array, str) =>
!!array.find((item) =>
Array.isArray(item) ? checkElement(item, str) : item === str
);
const arr = [['one','two'],['three','four'],['five','six']];
console.log(checkElement(arr, 'four')); // true
console.log(checkElement(arr, 'seven')); // falseTry this code:
function checkElement(array){
for(value of array){
if(value.includes("some string")){return true}
}
return false
}
console.log(checkElement([["one","two"],["three","four"],["five","six"]]))
console.log(checkElement([["one","two"],["three","four"],["five","some string"]]))
publicfrom?