Syntax Error in If-Else Statement in Python [duplicate]

Question

Why is there a syntax error in this code on line 5?

n=int(input("Enter n:"))
if 1<x and 5>=x:
    if n%2==0:
        print("Wierd")
        else:
            print("Not Wierd")
            elif 5<n and 20=<n:
                if n%2==0:
                    print("Not Wierd")
                    else:
                        print("Wierd")
                        elif n>20:
                            if n%2==0:
                                print("Wierd")
                                else:
                                    print("Not Wierd")

Sometimes running a code checker like pep8online.com can help run down they syntax errors. — ShellNinja
– ShellNinja, Commented Aug 22, 2018 at 12:27

Some programmer dude · Accepted Answer · 2018-08-22 11:43:52Z

2

The else and elif should not be indented that much. They should be on the same indentation-level of the if they match:

n=int(input("Enter n:"))
if 1<x and 5>=x:
    if n%2==0:
        print("Wierd")
    else:
        print("Not Wierd")
elif 5<n and 20=<n:
    if n%2==0:
        print("Not Wierd")
    else:
        print("Wierd")
elif n>20:
    if n%2==0:
        print("Wierd")
    else:
        print("Not Wierd")

answered Aug 22, 2018 at 11:43

Some programmer dude

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Comments

Talha Junaid · Accepted Answer · 2018-08-22 11:48:08Z

0

On the line no. 5 you have extra indented else. there is another issue on line 7 elif must have if before and it can't be written after else

answered Aug 22, 2018 at 11:48

Talha Junaid

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