'numpy.float64' object cannot be interpreted as an integer

Question

Here is the code in question:

arr = ['-0.944', '0.472', '0.472']
charges = [np.float64(i) for i in arr] # [-0.944, 0.472, 0.472]
charges = np.ndarray(charges)

The error is thrown on the last step, where the list is casted to an ndarray. Assigning dtype=np.float64 in ndarray does not change the error. What is wrong with this snippet of code?

Numpy 1.14, Python 3.6.1

The constructor you're looking for is array, not ndarray. Calling ndarray directly is unusual. — user2357112
– user2357112, Commented Jun 25, 2018 at 16:07

Ramesh-X · Accepted Answer · 2018-06-25 16:25:34Z

4

The first argument to np.ndarray is the shape, which is usually a tuple of integers.

You should not use the low-level constructor np.ndarray. Correct interface is np.array, and take it directly from the strings without a list comprehension first:

>>> arr = ['-0.944', '0.472', '0.472']
>>> np.array(arr, dtype=np.float64)
array([-0.944,  0.472,  0.472])

edited Jun 25, 2018 at 16:25

Ramesh-X

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answered Jun 25, 2018 at 16:09

wim

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1 Comment

Eric Taw Over a year ago

Thanks -- rookie mistake!

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