I have this array
const arr = ['1','2','3',...'30','31','LAST']
I need to sort by number ASC
Here is the example code and I don't know how to sort it. help me please
const arr2 = ['2','1','10','LAST','20']
I need result ['1','2','10','20','LAST'] instead of ['1','10','2','20','LAST']
You could check for NaN and move that value to bottom.
Array#sort sorts without callback by string and does not respect stringed numerical values.
var array = ['2','ZIRST','1','10','LAST','20', 'Sara'];
array.sort((a, b) => isNaN(a) - isNaN(b) || a - b || a > b || -(a < b));
console.log(array);
function sortArray(arr) {
let sortedArr = arr.sort();
sortedArr.forEach((v, i) => {
if (!isNaN(parseInt(v))) {
sortedArr[i] = parseInt(v);
} else {
sortedArr[i] = v;
}
});
return sortedArr.sort((a, b) => a - b).map(String);
}
// tests
console.log(sortArray(['2', '1','10','LAST','20']));
console.log(sortArray(['5','ZIRST','1','10','LAST','20', 'Sara']));You need to check whether the given element in the array is number or not and then sort it accordingly for numbers and strings. You can create a reusable function sortNumber so that it can be used for multiple arrays and you do not need to duplicate the same logic again and again.
function sortNumber(a,b) {
return isNaN(a) - isNaN(b) || a - b;
}
var inputArray = ['2','1','10','LAST','20'];
inputArray.sort(sortNumber);
console.log(inputArray);
inputArray = ['21','31','110','LAST','220'];
inputArray.sort(sortNumber);
console.log(inputArray);You can use localeCompare to sort an array on the numeric property.
const array = ["1", "5", "10", "20", "ZERO", "LAST", "Sara"];
array.sort((a, b) => a.localeCompare(b,undefined,{numeric: true}));
console.log(array);You can use custom comparator like this:
var arr = ['2','1','10','LAST','20'];
arr.sort((a,b)=>{
return parseInt(a) > parseInt(b) || isNaN(a);
});
