Split array objects into array groups in swift 3

Question

I have an array like below:

let totalArr = ["First","Second","Third","Fourth","First","Second", "Second"]

My Required output is:

let grouper = [["First","First"],["Second", "Second", "Second"],["Third"],  ["Fourth"]]

can anybody give optimal iterations?

You're asking an open-ended algorithm question - this might not do so well on SO. SO is meant for "I tried this. It's broken. I also tried this. What am I doing wrong?" type of questions. — JaredH
– JaredH, Commented May 22, 2018 at 12:44
I guess he wants something like grouping not sure if duplicate answer is same. — TheTiger
– TheTiger, Commented May 22, 2018 at 12:58
@TheTiger: Already reopened – I had misread the question, sorry about that! — Martin R
– Martin R, Commented May 22, 2018 at 12:59
@MartinR Oh my page was not refreshed. :) And I had the answer which now already has given by Abdelahad. — TheTiger
– TheTiger, Commented May 22, 2018 at 13:01
@TheTiger consider it your answer upvote it and get sportman badge — Abdelahad Darwish
– Abdelahad Darwish, Commented May 22, 2018 at 13:09

Abdelahad Darwish · Accepted Answer · 2018-05-22 12:57:57Z

6

 let totalArr = ["First","Second","Third","Fourth","First","Second", "Second"]

 let grouper =   (Dictionary(grouping: totalArr, by: { $0})).map {  $0.value}

 print(grouper)

or

  let arranged =   (Dictionary(grouping: totalArr, by: { $0})).values
 print(arranged)

answered May 22, 2018 at 12:57

Abdelahad Darwish

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Comments

Malleswari · Accepted Answer · 2018-05-22 12:57:56Z

3

You can use Dictionay's grouping function to make a group and then get all values.

let totalArr = ["First","Second","Third","Fourth","First","Second", "Second"]

let group = Dictionary(grouping: totalArr) { (object) -> String in
    let lowerBound = String.Index(encodedOffset: 0)
    let upperBound = String.Index(encodedOffset: 1)
    return String(object[lowerBound...upperBound])
}
print("group :\(group.values)")

answered May 22, 2018 at 12:57

Malleswari

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Comments

Gaurav Bharti · Accepted Answer · 2018-05-22 13:09:22Z

3

try this :)

You can pass any String array to the function and it will return your desired result:

func groupArr(totalArr: [String]) -> [Any]{
    var grouperArr = [[String]]()
    for i in totalArr{
        let arr = totalArr.filter({($0 == i)}) as [String]
        if(grouperArr.contains(arr) == false){
            grouperArr.append(arr)
        }
    }
    return grouperArr
}

edited May 22, 2018 at 13:09

Gaurav Bharti

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answered May 22, 2018 at 12:55

Abhay Singh

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1 Comment

TheTiger Over a year ago

Why return type is [Any] instead of [[String]] or Array<Array<String>> ?

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