generate file hash in python

Question

hi this code generate sha1 hash but hash differ from other tools generate sha1 hash from this file:

import os
import hashlib

fileList = os.listdir("D:\\a\\")
for i in fileList:
d=(hashlib.sha1(file("D:\\a\\"+i, 'r').read()).hexdigest())
# os.rename(i,d)
print(d)

in MD5 so i have this problem!! why?

edit: 'rb' solve my problem

not sure sha1 always generate same hash or not but you may try with "rb" — YOU
– YOU, Commented Feb 12, 2011 at 12:53
Maybe because you're using sha1hash in Python and comparing it to a MD5 hash? If this is not it, consider rewriting the question, it's pretty difficult to make sense of it. — lubomir.brindza
– lubomir.brindza, Commented Feb 12, 2011 at 12:54
MD5: en.wikipedia.org/wiki/MD5; SHA1: en.wikipedia.org/wiki/SHA-1 — imbaer
– imbaer, Commented Feb 12, 2011 at 13:00

cbz · Accepted Answer · 2011-02-12 13:01:17Z

8

Try using 'rb' and also try using the md5 method - at present you are using SHA1 - which is a different algorithm, and I presume from your explanation that the other tools are using md5.

answered Feb 12, 2011 at 13:01

cbz

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Michael · Accepted Answer · 2013-03-22 01:53:17Z

1

import os
import hashlib

fileList = os.walk("c:\\temp")
for tuple in fileList:
    for item in tuple[2]:
        d = hashlib.md5(file(tuple[0] + "\\" + item, 'r').read()).hexdigest()
        print [item, d]

answered Mar 22, 2013 at 1:53

Michael

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