We were going through the Array.prototype.sort() MDN documentation, where we saw an example:
var array1 = [1, 2,3,4,5,6,7,8,9,10];
array1.sort();
console.log(array1);
So the expected output is
[1, 2, 3 , 4, 5, 6, 7, 8, 9, 10]
But insted of this we got
[1, 10, 2, 3, 4, 5, 6, 7, 8, 9]
Why isn’t it sort as we expected?
You need to use a sort function. By default sort uses alphabetic sorting instead of numeric.
array1.sort(function (a,b) {
return a - b; // Ascending
});
array1.sort(function (a,b) {
return b - a; // Descending
});
It is from the from the reference of This post
var numArray = [1, 2,3,4,5,6,7,8,9,10];
for (var i = 0; i < numArray.length; i++) {
var target = numArray[i];
for (var j = i - 1; j >= 0 && (numArray[j] > target); j--) {
numArray[j+1] = numArray[j];
}
numArray[j+1] = target
}
console.log(numArray);
function sorter(a, b) {
if (a < b) return -1; // any negative number works
if (a > b) return 1; // any positive number works
return 0; // equal values MUST yield zero
}
[1, 2,3,4,5,6,7,8,9,10].sort(sorter);
Please use the following code:
var array1 = [1, 2,3,4,5,6,7,8,9,10];
array1.sort(function(a,b){
return parseInt(a) > parseInt(b);
}
);
console.log(array1);
You can pass a function to sort method, For Asc sort :
array1.sort(function(a,b){return a>b?1:b>a?-1});
