split java log line with regex

Question

I'm trying to split a log line which looks like this:

15:10:10,408 INFO <NioProcessor-11> Raw Message: 8=FIXT.1.1|9=317|35=D|49=verifix|

into something like this:

15:10:10 
408
INFO
NioProcessor-11
FIXT.1.1
317
D
verifix

each information in split.

I have tried to split it with the split function with only

mystring.split((,)| \\\|) which splits my code to something like that:

15:10:10
408 INFO <NioProcessor-11> Raw Message: 8=FIXT.1.1
9=317
35=D
49=verifix

Then I took the second split 408 INFO <NioProcessor-11> Raw Message: 8=FIXT.1.1 and do a substring. It worked, but not perfectly because sometimes the second split is longer or shorter and it doesn't look to be a good solution.

I would like to know if it's possible to split that string with regex expressions actually. I'm new to regex and I didn't find a way to write an expression that handles my objective.

it would be helpful if you can mention few more sample of log lines in your logfiles. Currently, it only mentioned a single pattern of logs. — CodeHunter
– CodeHunter, Commented Mar 2, 2018 at 20:18
How about a single split [, <>]|(?: Raw Message: )?\|?\d+=|\| — user557597
– user557597, Commented Mar 2, 2018 at 20:21

ctwheels · Accepted Answer · 2018-03-02 20:42:14Z

1

See regex in use here

(?:> [^:]+: |\d+=|[ ,|<>])+

(?:)+ Match any of the following options one or more times
- > [^:]+: Matches > , then one or more of any character except :, then :
- \d+= Match one or more digits, then =
- [ ,|<>] Match any character in the set

Result:

15:10:10
408
INFO
NioProcessor-11
FIXT.1.1
317
D
verifix

answered Mar 2, 2018 at 20:42

ctwheels

23k9 gold badges47 silver badges81 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

IEE1394 · Accepted Answer · 2018-03-02 20:17:02Z

0

if you search for a generic solution this could be helpful

    final String first = "15:10:10,408 INFO <NioProcessor-11> Raw Message: 8=FIXT.1.1|9=317|35=D|49=verifix|";
    final String second = "408 INFO <NioProcessor-11> Raw Message: 8=FIXT.1.1";

    String pattern = "[,| ]";
    Arrays.stream(first.split(pattern)).forEach(System.out::println);
    System.out.println("--------------------------");
    Arrays.stream(second.split(pattern)).forEach(System.out::println);

but if you want to get the specified elements, use groups and a specific pattern.

answered Mar 2, 2018 at 20:17

IEE1394

1,26915 silver badges36 bronze badges

3 Comments

patoCapongo93 Over a year ago

thank you for asking so your pattern split whether he find a( ',' space or pipe) what if i want to split these 8=FIXT.1.1|9=317 without those 8= & 9= =to=> FIXT.1.1 and 317 .. is there a way ?

IEE1394 Over a year ago

there are a lot of tools around regex search for "regex coach" or "regex tester" and use the one you like most. even for IDE (Eclipse for example) there are plugins

tero17 Over a year ago

youtube.com/… check this course

IEE1394 · Accepted Answer · 2018-03-02 20:38:23Z

0

@alaaeddine zammel thats more specific

    final String input = "8=FIXT.1.1|9=317";
    final String groupPattern = "\\d=([A-Z\\.\\d]*)\\|\\d=([A-Z\\.\\d]*)";
    final Pattern p = Pattern.compile(groupPattern);
    final Matcher m = p.matcher(input);
    if (m.matches()) {
        System.out.println(m.group(1));
        System.out.println(m.group(2));
    }

answered Mar 2, 2018 at 20:38

IEE1394

1,26915 silver badges36 bronze badges

Comments

Srdjan M. · Accepted Answer · 2018-03-02 21:03:02Z

0

Regex: (?:> Raw Message: |\|)?(?:\d+=|[ ,<|]+)

Details:

(?:> Raw Message: |\|)? Non-capturing group (?:) match > Raw Message: or | pipe \| if they exist ?
(?:\d+=|[ ,<|]+) Non-capturing group (?:) match digit one or unlimited times \d+ or | match a single character present in the list [ ,<|]+ one or unlimited times +

Java code:

String test = "15:10:10,408 INFO <NioProcessor-11> Raw Message: 8=FIXT.1.1|9=317|35=D|49=verifix|";
String[] data =test.split("(?:> Raw Message: |\\|)?(?:\\d+=|[ ,<|]+)");
for(String r : data) {
    System.out.println(r);
}

Output:

15:10:10
408
INFO
NioProcessor-11
FIXT.1.1
317
D
verifix

Code demo

edited Mar 2, 2018 at 21:03

answered Mar 2, 2018 at 20:28

Srdjan M.

3,4253 gold badges17 silver badges35 bronze badges

5 Comments

Srdjan M. Over a year ago

@alaaeddine zammel Practice a lot!

patoCapongo93 Over a year ago

any links or sources ?

Srdjan M. Over a year ago

@alaaeddine Just google. You can search right here with tag 'regex' and find a lot of simple examples that you can solve by your self. Use regex101 as a practice tool.

patoCapongo93 Over a year ago

thank you sorry can't upvote your response ~~cause im new to stack i will google :)

Srdjan M. Over a year ago

@alaaeddine zammel No problem. Glad I could help. See regex section of SO.

Collectives™ on Stack Overflow

split java log line with regex

4 Answers 4

Comments

3 Comments

Comments

5 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

Comments

3 Comments

Comments

5 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related