I would like to check if textField is empty or not and if empty, give specific text. I tried like below but it returns ""
let text = textField.text ?? "abc"
let value = ["text": text]
//put firebase database
ref.child("text").setValue(value)
How can I fix this? Thank you in advance!
The problem is you always get an empty string that's not nil. You can correct that as following:
let text = (textField.text ?? "").isEmpty ? "abc" : textField.text
text to be an Optional String, simply force-unwrap the second occurrence of textField.text in this answer: let text = (textField.text ?? "").isEmpty ? "abc" : textField.text!.
guard let text = (textField.text ?? "").isEmpty ? "abc" : textField.text else { return } I did like this. Is this bad approach?text to contain "abc" when textField.text is nil, that's not what you want.You have to make sure that the text property is not nil and also that it does not contain an empty string:
let text: String
if let textFieldText = textField.text, !textFieldText.isEmpty {
text = textFieldText
} else {
text = "abc"
}
Modifying Anton's answer slightly, you could use:
let text = (textField.text ?? "").isEmpty ? "abc" : textField.text!
(Force-unwrapping the 2nd occurrence of textField.text so text isn't an optional.)
In that case force-unwrapping is safe because the first ?? "nil coalescing operator will have handled the case where textField.text == nil.
If you don't want to use a force-unwrap, break the conversion into 2 lines:
let required = str ?? ""
let text = required.isEmpty ? "abc" : required
Daibaku, the solution you showed in the comments:
guard let text = (textField.text ?? "").isEmpty ? "abc" : textField.text else {
return
}
print(text)
Will return without executing the print statement (or whatever follows the guard) if textField.text == nil
