javascript remove multiple values of array of objects

If you can use ES6, try using JavaScript's filter and includes for this.

const nums = [1, 2, 3, 4, 5, 6];
const remove = [1, 2, 4, 6];

function removeFromArray(original, remove) {
  return original.filter(value => !remove.includes(value));
}

console.log(removeFromArray(nums, remove));

This will work just as well with strings.

const nums = ["1", "2", "3", "4", "5", "6"];
const remove = ["1", "2", "4", "6"];

function removeFromArray(original, remove) {
  return original.filter(value => !remove.includes(value));
}

console.log(removeFromArray(nums, remove));

This solution also has the added benefit of being immutable. Meaning that you are returning new data rather than morphing the old. Which is considered good practice.

https://wecodetheweb.com/2016/02/12/immutable-javascript-using-es6-and-beyond/

You just need to loop over that array, and check for the array element.

arrayToRemove = ['171', '172', '173', '174'];

for (i = arrayToRemove.length; i>=0; i--) {
   if(obj.findObjectByKey(response, 'cat_id', arrayToRemove[i]) == true) {
       var catId = response.map(item => item.cat_id).indexOf(arrayToRemove[i]);
       response.splice(catId, 1);
   } 
}

There are other ways to do this, but this is the fastest and most straight forward with least changes to your current code.

It's important to note that you should loop this from the end of the array to remove to the beginning so you can preserve indices of the other elements in the remaining array.

var users = [
  { user: 'barney', age: 36, active: true },
  { user: 'fred', age: 40, active: false },
  { user: 'travis', age: 37, active: true },
];
var app = [{ user: 'barney' }, { user: 'fred' }];
_.forEach(app, (v) => {
  users = _.reject(users, { user: v.user });
});

   var userList = [
      { name: 'abhijeet', city: 'pune', id: 1},
      { name: 'rohit', city: 'pune', id: 2},
      { name: 'vicky', city: 'deglur', id: 3},
      { name: 'abhilash', city: 'washim', id: 4},
      { name: 'sumit', city: 'nagpur', id: 5}
    ];

    var removeUsers = [
      { name: 'vicky', city: 'deglur', id: 3},
      { name: 'sumit', city: 'nagpur', id: 5}
    ];

    var idArray = removeUsers.map((user) => user.id);

    userList = userList.filter((item) => {
        return idArray.indexOf(item.id) === -1;
    });