Passing string variable to shell script

Question

I have a shell script contains this condition

 if [ -z "${PEER_ADDRESS}" ]; then
    ##some code here
fi

I'm not able to pass PEER_ADDRESS variable when I run the script.

I tried the below but it always executed the if code

./script.sh PEER_ADDRESS="someString" 
./script.sh $1 ="someString" 
./script.sh "someString"
./script.sh $PEER_ADDRESS="someString"

Please research other available solutions before asking. You want to run your third example in "what you tried", then the passed arg will be available in $1. See stackoverflow.com/questions/9732385, or unix.stackexchange.com/questions/32290 for a key=value notation being handled (it's just string processing; there's no magic "keyword args" function for passing things to Bash). — Zac B
– Zac B, Commented Jan 4, 2018 at 23:10
Note that your first attempt would work if you set the -k option first. — chepner
– chepner, Commented Jan 4, 2018 at 23:19
What do you mean, "didn't work"? If you run ./script.sh "someString", then "$1" within that script will certainly expand to someString, and a question that claims otherwise should include a minimal reproducible example allowing others to see the problem for themselves. — Charles Duffy
– Charles Duffy, Commented Jan 5, 2018 at 0:28
I stated in my question very clearly how the script referenced the variable..like this "${PEER_ADDRESS}" , that's why this way didn't work for me. — Fawzinov
– Fawzinov, Commented Jan 5, 2018 at 4:26

choroba · Accepted Answer · 2018-01-04 23:10:37Z

3

The assignment precedes the command:

PEER_ADDRESS="someString" ./script.sh

answered Jan 4, 2018 at 23:10

choroba

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