Calling pointer receiver method with non pointer value [duplicate]

Question

Please see the code below. I know it as a fact that a non pointer receiver can accept pointer and non-pointers values but a pointer receiver can only accept a pointer value. That being said, I fail to understand how the last call works and the second-last doesn't. (Run Here)

The issue is that I am able to call a Pointer Receiver method from non pointer method. That is not explained in the other similar question. That answer explains only about the pointer calling pointer receiver method.

package main

import (
    "fmt"
)

type person struct {
    name string
}

type human interface {
    speak() string
}

func (p *person) speak() string {
    return "Speak() called by " + p.name
}

func saySomething(h human) {
    fmt.Println("area", h.speak())
}

func main() {
    p := person{"harsh"}
    //works
    saySomething(&p)

    //doesn't work
    //saySomething(p)

    //works
    p.speak()
}

Also a good read on the subject: blog.golang.org/laws-of-reflection — Kaedys
– Kaedys, Commented Dec 15, 2017 at 17:16

Andy Schweig · Accepted Answer · 2017-12-15 03:55:28Z

2

The second call doesn't work because the type person doesn't implement the human interface (only *person does). The "magic" that allows you to call a method with a pointer receiver on a non-pointer value and vice versa only applies to those specific cases. When assigning a value to an interface variable or field or passing it as a parameter that expects an interface, the type of the value must implement the interface.

If you were to call p.speak(), the compiler would automatically change that to (&p).speak(). A similar conversion happens in the other direction if you have a method with a non-pointer receiver and you call it on a pointer.

answered Dec 15, 2017 at 3:55

Andy Schweig

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