Javascript replace all duplicate characters in an array the same way

Question

I'm replacing all characters in an array with random letters/numbers. However, duplicate letters do not get the same values which is what I want.

var rWords = ["all","ball","balloon"];
var word = rWords[Math.floor(Math.random() * rWords.length)];

var letters = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
var getPos = function(arr) {
    return Math.floor(Math.random() * arr.length);
}

var arr = word.split('');
for (var i = 0; i < word.length; i++) {
    arr.splice(getPos(arr), 1, letters[getPos(letters)]);
}
word = arr.join('');

I want the output to be something like:
all = 4xx, ball = Y4xx, balloon = Y4xxRR1

It was this "duplicate letters do not get the same values" property which helped lead to the downfall of the Enigma machine. — James
– James, Commented Dec 4, 2017 at 21:37

ibrahim mahrir · Accepted Answer · 2017-12-04 21:19:52Z

2

create a map function that return unique char for same input (for each character we want to replace we check if we already have a replacement for it stored in _map, if not then we find one and use it and store it in _map for future use)

var rWords = ["all","ball","balloon"];

var letters = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";

var _map = {}
function map(char) {
    if (_map[char] === undefined) {
        _map[char] = letters[Math.floor(Math.random() * letters.length)]
    }
    return _map[char]
}
var result = rWords.map(function(word) {
    var arr = word.split('');
    for (var i = 0; i < word.length; i++) {
        arr.splice(i, 1, map(arr[i]));
    }
    return arr.join('');
})

console.log(result);

edited Dec 4, 2017 at 21:19

ibrahim mahrir

31.8k5 gold badges50 silver badges78 bronze badges

answered Dec 4, 2017 at 21:13

Farnabaz

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