In TypeScript I want distinct values from comma separated duplicate string:
this.Proid = this.ProductIdList.map(function (e) { return e.ProductId;}).join(',');
this.Proid = "2,5,2,3,3";
And I need :
this.Proid = "2,5,3";
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Take a look at this: stackoverflow.com/a/16747921/5309449Venomy– Venomy2017-11-10 11:13:29 +00:00Commented Nov 10, 2017 at 11:13
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Does this answer your question? Get all unique values in a JavaScript array (remove duplicates)Michael Freidgeim– Michael Freidgeim2020-05-08 13:42:35 +00:00Commented May 8, 2020 at 13:42
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2 Answers
This can be simply done with with ES6,
var input = [2,5,2,3,3];
var test = [ ...new Set(input) ].join();
DEMO
var input = [2,5,2,3,3];
var test = [ ...new Set(input) ].join();
console.log(test);EDIT
For ES5 and below, you can try,
var input = [2,5,2,3,3];
var test = Array.from(new Set(input).values()).join();
console.log(test);7 Comments
mickaelw
I have this error: "TypeError: (intermediate value).slice is not a function at tutocefano.js:7:29" with your answer? Maybe it's JsBin?
mickaelw
Yes I know it’s very strange... I just copy/past your code in jsbin and console log of test
Sajeetharan
check the demo above
John Weisz
@mickaelw -- See the code that the array destructuring statement
[ ...set ] is compiled to, for ES5 target and below it will use slice to do the shallow array copy. The browser in question simply doesn't support it, and needs a polyfill.John Weisz
Also, this answer will be giving a compile error on targets below ES6.
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One possible solution:
this.ProductIdList = ["2","5","2","3","3"]
const tab = this.ProductIdList.reduce((acc, value) => {
return !acc.includes(value) ? acc.concat(value) : acc
}, []).join(',');
console.log(tab) //"2,5,3"
You can do in one line too:
this.ProductIdList = ["2","5","2","3","3"]
const tab = this.ProductIdList.reduce((acc, value) => !acc.includes(value) ? acc.concat(value) : acc, []).join(',');
console.log(tab) //"2,5,3"