Extract especific URL from String in java

Question

I have a String like this:

.........e1.whatsapp.net..............>.ns1.p13.dynect..hostmaster.whatsapp.com.x:a>.......X..:....

And I need to extract the first URL:

e1.whatsapp.net

I was trying with the solution in this post but not working for me, maybe because the amount of dots. Maybe if I try with another pattern regex, but I know nothing about "regex".

Any sugestion?

hostmaster.whatsapp.com is also URL. Is there any pattern for your URL ? — Shubhendu Pramanik
– Shubhendu Pramanik, Commented Nov 4, 2017 at 3:32
Try to temporarily replace >1 number of dots (.) by some character that's not in regex like > and apply the same regex removing \\b(https?|ftp|file):// since your URLs don't have https etc before the address. — CS_noob
– CS_noob, Commented Nov 4, 2017 at 3:36
the pattern can be any kind of URL, like: www.google.com, stackoverflow.com, github.com, asdf.ru, and etc. the most important thing is the dots who separate the domain and the host. — lcpr_phoenix
– lcpr_phoenix, Commented Nov 4, 2017 at 3:40

Buddhi · Accepted Answer · 2017-11-04 04:18:40Z

0

This code below may help you to extract the email with using regex.

class StringSeperator {

  public static void main(String args[]){
    String urlString = ".........e1.whatsapp.net..............>.ns1.p13.dynect..hostmaster.whatsapp.com.x:a>.......X..:....";
    String array[] = urlString.split("\\.\\.+"); 
    System.out.println(array[1]);
  }
}

Here I use regex as \\.\\.+ which means two or more dots. The string split using two or more dots.

If I further explain about regex. Here I use \\. for depicting the dot and use + for saying one or more occurrences of a dots. For more details about Java regex please follow below link.

https://www.tutorialspoint.com/java/java_regular_expressions.htm

answered Nov 4, 2017 at 4:18

Buddhi

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