I am trying to assign each person an age value from a list with same size.
class Person
attr_accessor :age
end
a = [person1, person2, person3, person4, person5]
b = [1,2,3,4,5]
How can I do the assignment below using a neat way(without using index i)?
i = 0
a.each do |p|
p.age = b[i]
i += 1
end
If they are guaranteed to be the same length, then you can use zip:
a.zip(b).each do |p, age|
p.age = age
end
As @ardavis pointed out, zip takes a block so you can remove the .each.
I know you asked for a solution without an index, but note that your code can be made neater even with an index. In Ruby, you don't need to define and increment your own index. Instead, you can use with_index like so:
a.each.with_index do |p, i|
p.age = b[i]
end
.each, zip takes a block. a.zip(b) { |a, b| a.age = b }You can use index (as each Person instance is going to be unique):
a.each { |ai| ai.age = b[a.index(ai)] }
P.S. I would go with the approach introduced by @ardavis, using just zip:
a.zip(b) { |a, b| a.age = b }