I have a list of lists and I want to find the max value by one index in the lists, in this case [5].
Once I have the max value, how would I find where that occurs and return the first element of that list?
For example:
inputlist = [[70, 'Cherry St,', 43.684371, -79.316756, 23, 9, 14, True, True],
[78, 'Cow Rd', 43.683378, -79.322961, 15, 13, 2, True, False]]
How can I get my function to return 78 as it contains the maximum value of index[5] in my list of lists?
Use the max() function, but pass through an argument to check a specific index:
max(inputList, key=lambda x: x[5])
This returns the sublist in inputList that has the greatest value at index 5. If you want to actually access this value, add [5] to the end of the statement.
Since it seems that you want the ID of the list with the maximum 5th element, add [0] to the end:
max(inputList, key=lambda x: x[5])[0]
itemgetter instead of lambda stackoverflow.com/questions/17243620/…, Though no difference in small-medium lists.
max() function, but that kinda goes against the whole idea of Python
lambda or itemgetter get them?This is what you can do, using list comprehension twice
inputlist = [[70, 'Cherry St,', 43.684371, -79.316756, 23, 9, 14, True, True],
[78, 'Cow Rd', 43.683378, -79.322961, 15, 13, 2, True, False]]
The max value at the 5th index , considering all the list in inputlist. You can use this for any(n) no of member list.
value_5th = max([listt[5] for listt in inputlist])
Once you reach at that:
This will give you the first element of that member list which has that largest/max element at the 5th index amongst all other member list.Plz note that this will work even if multiple member lists have same max element at their 5th index
Your_ans = [ listt[0] for listt in inputlist if value_5th in listt]
Just trying to give you a more robust solution.Although ans given above is quite clever in my view.
