php mysql forms validation

Question

i already got message in my browser

Notice: Undefined variable: password in C:\xampp\htdocs\udemy\mysql\login.php on line 8 pls insert username and password

even i haven't submitted the form.

One more question how can i validate if the username and the password are submit with text.

<?php

if(isset($_POST['submit'])){
$username = $_POST['username'];
$password = $_POST['password'];
}

if($username && $password){
    echo $username;

    echo $password;
}else{
    echo "pls insert username and password";
}


?>



<!DOCTYPE html>
<html>
<head>
<title>Document</title>
<link rel="stylesheet"
href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.2/css/bootstrap.min.css"
>
</head>
<body>  
<div class="container">

    <div class="col-sm-6">
        <form action="login.php" method="POST">
            <div class="form-group">
                <label for="username">Username</label>
                <input type="text" name="username"
                class="form-control">
            </div>

            <div class="form-group">
                <label for="username">Password</label>
                <input type="password" name="password"
                class="form-control">
            </div>

            <div class="form-group">
                <input type="submit" name="submit"
                class="btn btn-primary">
            </div>

        </form>
    </div>

</div>
</body>
</html>

If $_POST['submit'] is not set you aren't defining the variables you are trying to use in the next conditional. Put the second conditional inside the first one. Your if(isset($_POST['submit'])){ is checking if the form was submitted. — chris85
– chris85, Commented Sep 25, 2017 at 3:59
@always-a-learner 1 more thing how come this if statement check if the username and the password was inputed. it looks like there's no logic in the statement. if($username && $password){ echo $username; echo $password; }else{ echo "pls insert username and password"; } — Josel Parayno
– Josel Parayno, Commented Sep 25, 2017 at 4:25

Fokrule · Accepted Answer · 2017-09-25 04:11:49Z

Declare $username=$password='' before if(isset($_POST['submit']))

Maybe this could help you. Do modify in this code , but from this code you will get your error answer and also validation for you `

 $username=$password=''
 $valid=true;


if ($_SERVER["REQUEST_METHOD"] == "POST") {

if (empty($_POST["username"])) {

        $valid=false; 
      } 
      else {
        $username = test_input($_POST["username"]);

        if (!preg_match("/^[a-zA-Z ]*$/",$username)) {
          echo 'User name only suppost space and letter';
          $valid=false;
        }
      }



       if (empty($_POST["password"])) {
        echo 'password can't be empty;
        $valid=false;
      } else {
        $password = test_input($_POST["password"]);

      }

     if($valid)

        {

            include('db_connect.php');

            $sql = "INSERT INTO tbl_user (id,username,password) VALUES 
 ('','$username',$password')";



            $conn->close();


        }           

 }



function test_input($data) {
$data = trim($data);
$data = stripslashes($data);
$data = htmlspecialchars($data);
return $data;
}

?>`

always-a-learner · Accepted Answer · 2017-09-25 03:59:13Z

0

<?php

if(isset($_POST['submit'])){
$username = $_POST['username'];
$password = $_POST['password'];

    if(isset($username) && isset($password)){
        echo $username;

        echo $password;
    } else{
        echo "pls insert username and password";
    }

}

?>

answered Sep 25, 2017 at 3:59

always-a-learner

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